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What is the Area of a regular hexagon with a base of 10 and an apothem of 20?
12 x 5 x 20 ie 1200squnits. I'm not convinced you can have such a hexagon, if the side is 10 then shouldn't the apothem have to be 5 root 3?
Find the area of the regular hexagon described in the question above?
Let s be the length of a side of the hexagon and let h be the the apothem 6(1/2sh) it the area of 3sh.
What is the area of a regular hexagon with a side of 4 and an apothem of 3 46?
Easy. Since the side is the base and the apothem is the height of the triangle, multiply them and divide by two to get the area of the triangle. 3 * 3.46 = 10.38 /2 = 5.19. Then multiply by 6 to get the area of the hexagon. 5.19 * 6 = 31.14. You multiply by 6 because you can fit 6 regular triangles in a regular hexagon. We've already found the area of one regular triangle in the hexagon.
What is the area of a regular hexagon if a side is 30?
The area is about 2338.27 square units, from the formulaA = 3/2 (sqrt 3) s2 or about 2.598 s2--Let's draw a segment from the center of the hexagon to the middle of a side. This segment is called the apothem. Then use the 30-60-90 triangle rule. If half of a side is 15, that means the apothem is 15√3.If we divide the hexagon into equilateral triangles, we get 6 equilateral triangles.So if we find the area for one of these triangles and multiply it by 6, we get the area of the hexagon. The area of a triangle is found by 1/2(b*h). The apothem is your height for the triangles. So plug the numbers in: 1/2(30*15√3). Solve: 1/2(779.4228) = 389.7114. This is the area of one triangle. Now we multiply by 6, and this becomes: 2338.2686
What is the area of a regular hexagon with apothem 6?
Draw incircle and circumcircle. radius of incircle = 6 radius of circumcircle = 6 × 2/√3 = 12/√3 (side opposite to 60° is √3/2 times hypotenuse. consider right angled triangle formed by these two radius and 1/2 side of hexagon. (1/2 side)² = (12/√3)² - 6² = 12 1/2 side = √12 full side of hexagon = 2√12, perimeter = 12√12 Area = 1/2 a × perimeter = 1/2 × 6 × 12√12 = 36√12 = 72√3 unit²
What is the area of a reagular hexagon with the side length of 10?
The area of a reagular hexagon with the side length of 10 is 51.96 square units
What is the area of a regular hexagon if each sides is 11m the apothem is 9m and the radius is 10m?
297 M
What is the perimeter of a hexagon having 225 cm square area of a circle inscribed in it?
Area of circle = 225 cm2 implies radius = 8.46 cm (approx) Therefore, apothem of hexagon = 8.46 cm then side of hexagon = apothem*2/sqrt(3) = 9.77 cm (approx) and so perimeter = 6*side = 58.63 cm
What is the area of a hexagon with apothem of 0.88m?
It is approx 2.68 square metres.
How do you find the area of a hexagon without a side length?
To find the area of a Regular hexagon with side length (x) you need:1. The "radius" of the hexagon. (Just the length from the center to the outside edge.)2. The apothem. (which is only just half of the height of the base.)**If you don't have one or both of these you can't do it.**Steps:1. Make a triangle of the apothem (used as a) and the radius. (r)2. Use the Pythagorean Theorem to find 1 half of the side length.3. Multiply the actual side length by 6.4. Multiply that by a.5. The area is your answer.
Find the area of a regular hexagon with a base of 10 and an apothem of 12?
14
How do you find the area of a square using the radius and the apothem?
For a SQUARE, the area is (2r)2 because the length and width are the same. The apothem (radius) is used to find the area of other regular polygons.
What is the area of a regular hexagon with apothem length of 24 inches?
For a regular hexagon, half the side length can be calculated from the apothem via trigonometry: half_side_length = apothem x tan 30° Then: area = apothem x 1/2 x perimeter = apothem x 1/2 x side_length x 6 = apothem x half_side_length x 6 = 24 in x (24 in x tan 30°) x 6 ≈ 1995 sq in
What is the Area of a regular hexagon with a base of 10 and an apothem of 20?
12 x 5 x 20 ie 1200squnits. I'm not convinced you can have such a hexagon, if the side is 10 then shouldn't the apothem have to be 5 root 3?
Find the area of the regular hexagon described in the question above?
Let s be the length of a side of the hexagon and let h be the the apothem 6(1/2sh) it the area of 3sh.
What is the area of a hexagon with a radius of 10?
3002m
How do you find the area of a regular hexagon whose apothem is 1.7cm and side length is 2cm?
To find the area of a regular hexagon, you can use the formula: Area = (Perimeter × Apothem) / 2. The perimeter of the hexagon is 6 times the side length, so for a side length of 2 cm, the perimeter is 12 cm. Substituting the values into the formula gives: Area = (12 cm × 1.7 cm) / 2 = 10.2 cm². Thus, the area of the hexagon is 10.2 cm².
