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Area of a reagular hexagon if each side is 11m the apothem is 9 and radius 10?
Wiki User
∙ 14y ago
We don't need the measure of the radius since we know the measure length of the side and of the apothem, which we use to find the area of one of the triangles that are formed by connecting the center with the vertices of the hexagon. So,
A = 6[(1/2)(11 x 9)] = 297 m2
Wiki User
∙ 14y ago
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What is the Area of a regular hexagon with a base of 10 and an apothem of 20?
12 x 5 x 20 ie 1200squnits. I'm not convinced you can have such a hexagon, if the side is 10 then shouldn't the apothem have to be 5 root 3?
Find the area of the regular hexagon described in the question above?
Let s be the length of a side of the hexagon and let h be the the apothem 6(1/2sh) it the area of 3sh.
What is the area of a regular hexagon with a side of 4 and an apothem of 3 46?
Easy. Since the side is the base and the apothem is the height of the triangle, multiply them and divide by two to get the area of the triangle. 3 * 3.46 = 10.38 /2 = 5.19. Then multiply by 6 to get the area of the hexagon. 5.19 * 6 = 31.14. You multiply by 6 because you can fit 6 regular triangles in a regular hexagon. We've already found the area of one regular triangle in the hexagon.
What is the area of a regular hexagon if a side is 30?
The area is about 2338.27 square units, from the formulaA = 3/2 (sqrt 3) s2 or about 2.598 s2--Let's draw a segment from the center of the hexagon to the middle of a side. This segment is called the apothem. Then use the 30-60-90 triangle rule. If half of a side is 15, that means the apothem is 15√3.If we divide the hexagon into equilateral triangles, we get 6 equilateral triangles.So if we find the area for one of these triangles and multiply it by 6, we get the area of the hexagon. The area of a triangle is found by 1/2(b*h). The apothem is your height for the triangles. So plug the numbers in: 1/2(30*15√3). Solve: 1/2(779.4228) = 389.7114. This is the area of one triangle. Now we multiply by 6, and this becomes: 2338.2686
What is the area of a regular hexagon with apothem 6?
Draw incircle and circumcircle. radius of incircle = 6 radius of circumcircle = 6 × 2/√3 = 12/√3 (side opposite to 60° is √3/2 times hypotenuse. consider right angled triangle formed by these two radius and 1/2 side of hexagon. (1/2 side)² = (12/√3)² - 6² = 12 1/2 side = √12 full side of hexagon = 2√12, perimeter = 12√12 Area = 1/2 a × perimeter = 1/2 × 6 × 12√12 = 36√12 = 72√3 unit²
What is the area of a reagular hexagon with the side length of 10?
The area of a reagular hexagon with the side length of 10 is 51.96 square units
What is the area of a regular hexagon if each sides is 11m the apothem is 9m and the radius is 10m?
297 M
What is the perimeter of a hexagon having 225 cm square area of a circle inscribed in it?
Area of circle = 225 cm2 implies radius = 8.46 cm (approx) Therefore, apothem of hexagon = 8.46 cm then side of hexagon = apothem*2/sqrt(3) = 9.77 cm (approx) and so perimeter = 6*side = 58.63 cm
What is the area of a hexagon with apothem of 0.88m?
It is approx 2.68 square metres.
How do you find the area of a hexagon without a side length?
To find the area of a Regular hexagon with side length (x) you need:1. The "radius" of the hexagon. (Just the length from the center to the outside edge.)2. The apothem. (which is only just half of the height of the base.)**If you don't have one or both of these you can't do it.**Steps:1. Make a triangle of the apothem (used as a) and the radius. (r)2. Use the Pythagorean Theorem to find 1 half of the side length.3. Multiply the actual side length by 6.4. Multiply that by a.5. The area is your answer.
Find the area of a regular hexagon with a base of 10 and an apothem of 12?
14
How do you find the area of a square using the radius and the apothem?
For a SQUARE, the area is (2r)2 because the length and width are the same. The apothem (radius) is used to find the area of other regular polygons.
What is the area of a regular hexagon with apothem length of 24 inches?
For a regular hexagon, half the side length can be calculated from the apothem via trigonometry: half_side_length = apothem x tan 30° Then: area = apothem x 1/2 x perimeter = apothem x 1/2 x side_length x 6 = apothem x half_side_length x 6 = 24 in x (24 in x tan 30°) x 6 ≈ 1995 sq in
What is the Area of a regular hexagon with a base of 10 and an apothem of 20?
12 x 5 x 20 ie 1200squnits. I'm not convinced you can have such a hexagon, if the side is 10 then shouldn't the apothem have to be 5 root 3?
Find the area of the regular hexagon described in the question above?
Let s be the length of a side of the hexagon and let h be the the apothem 6(1/2sh) it the area of 3sh.
What is the area of a hexagon with a radius of 10?
3002m
What is the area of a regular hexagon with a side of 4 and an apothem of 3 46?
Easy. Since the side is the base and the apothem is the height of the triangle, multiply them and divide by two to get the area of the triangle. 3 * 3.46 = 10.38 /2 = 5.19. Then multiply by 6 to get the area of the hexagon. 5.19 * 6 = 31.14. You multiply by 6 because you can fit 6 regular triangles in a regular hexagon. We've already found the area of one regular triangle in the hexagon.
