one way is to let x^2=m, then you have an equation m^2+3m-28=0, and then you solve this quadratic equation for m, and you get: m=4, or m=-7... since m represents x^2, m can only be positive (if we are dealing with real numbers), so m=-7 is not possible solution... now if m=4, the x^2=4, and solving this equation: x=2 or x=-2
m / 3/4 = 28 is the same as m = 3/4 x 28 = 21
2/12 = m/18 ie 12 x m = 2 x 18 ...
What do you mean by "solve"? Do you want to rearrange it, solving for x? That would be: x = (y - b) / m Do you want to find it's derivative with respect to x? Then the answer is: y' = m Do you want to find it's indefinite integral? That'd be: ∫y dx = mx2/2 + bx + C
If y = mx + b, then x = (y-b)/m (for m not equal to zero).
y-b/x=m
one way is to let x^2=m, then you have an equation m^2+3m-28=0, and then you solve this quadratic equation for m, and you get: m=4, or m=-7... since m represents x^2, m can only be positive (if we are dealing with real numbers), so m=-7 is not possible solution... now if m=4, the x^2=4, and solving this equation: x=2 or x=-2
It depends on which variable you wish to solve for.
1 m = 1,000 mm x m = 2,468 mm x/1 = 2,468/1,000 cross multiply and solve for x x = 2,468/1,000 x = 2.468 m
m<1=(5x-35) m<=(x+65)
the answer is: (y-b)/x = m y = mx + b y - b = mx (y-b)/x = m
IM A BTS ARMY
y = mx + b
m / 3/4 = 28 is the same as m = 3/4 x 28 = 21
2/12 = m/18 ie 12 x m = 2 x 18 ...
It depends on what you are trying to solve for. Here is a solution for x... y = mx + b y - b = mx (y - b) / m = x Note: If m is zero, then there is no solution, because the line is horizontal
What do you mean by "solve"? Do you want to rearrange it, solving for x? That would be: x = (y - b) / m Do you want to find it's derivative with respect to x? Then the answer is: y' = m Do you want to find it's indefinite integral? That'd be: ∫y dx = mx2/2 + bx + C