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You don't solve it!!! It is a method of manipulation of indices. a^(n) X a^(m) = a^(n+m) Similarly, a^(n) / a^(m) = a^(n-m) [a^(n)]^(m) = a^(nm)
one way is to let x^2=m, then you have an equation m^2+3m-28=0, and then you solve this quadratic equation for m, and you get: m=4, or m=-7... since m represents x^2, m can only be positive (if we are dealing with real numbers), so m=-7 is not possible solution... now if m=4, the x^2=4, and solving this equation: x=2 or x=-2
m / 3/4 = 28 is the same as m = 3/4 x 28 = 21
2/12 = m/18 ie 12 x m = 2 x 18 ...
What do you mean by "solve"? Do you want to rearrange it, solving for x? That would be: x = (y - b) / m Do you want to find it's derivative with respect to x? Then the answer is: y' = m Do you want to find it's indefinite integral? That'd be: ∫y dx = mx2/2 + bx + C