x2 + 7x = 0 => x*(x + 7) = 0 => x = 0 or x + 7 = 0 so that x = 0 or x = -7
x2-7x-18 (x-9) (x+2) x=9 x=-2 X= either 9 or -2
Assuming that what you're looking for is the values of x: x2 + 7x = 8 x2 + 7x - 8 = 0 (x + 8)(x - 1) = 0 x is equal to either -8 or 1.
x2- 7x + 6 = 0 factor, (x-6)(x-1) = 0 x = 6 x = 1
x2-7x+12 = 0 (x-3)(x-4) = 0x=3,4
x2 + 7x = 0 => x*(x + 7) = 0 => x = 0 or x + 7 = 0 so that x = 0 or x = -7
x2 +7x = 30 x2 +7x - 30 = 0 (x + 10)(x - 3) = 0 Now: x + 10 = 0 or x - 3 = 0 So: x = -10 or x = 3
x2 - 7x = 60 x2 - 7x - 60 = 0 (x - 12) (x + 5) = 0 x = 12 or x = -5
x=4 x=0
The value of x2+7x+10 depends on the value of X. If x=1, then x2+7x+10 = 18 If x=2, then x2+7x+10 = 28 If x=3, then x2+7x+10 = 40 and so forth
x2 + 7x + 9 = 3 ∴ x2 + 7x + 6 = 0 ∴ (x + 6)(x + 1) = 0 ∴ x ∈ {-6, -1}
x2 - 7x = 8 x2 - 7x - 8 = 0Now find two numbers that multiply to equal -8, and add to equal -7.(1) * (-8) = -8(1) + (-8) = -7(x+1)(x-8) = 0 This is the factored form of x2 - 7x = 8You can then solve the equation if necessary, and get:x = -1 or x = +8
x2-7x-18 (x-9) (x+2) x=9 x=-2 X= either 9 or -2
Assuming that what you're looking for is the values of x: x2 + 7x = 8 x2 + 7x - 8 = 0 (x + 8)(x - 1) = 0 x is equal to either -8 or 1.
x2+7x+12=0 x2+7x=-12 x+Sqaure Root of 7x= 2(SQ Root Symbol)3
7x-3=39 7x=42 x=6
X2+11x+11 = 7x+9 X2+11x-7x+11-9 = 0 x2+4x+2 = 0 Solve as a quadratic equation by using the quadratic equation formula or by completing the square: x = -2 + or - the square root of 2