Back in the day, regrouping in addition was called "carrying" and regrouping in subtraction was called "borrowing." I think "regrouping" is a better term for all of it. These problems might be easier to visualize if you copy them vertically. Example: 45 + 28 5 + 8 is 13, which won't fit in the ones place, so we leave 3 of the ones there and regroup the ten other ones into one ten which we add in the tens column. 1 + 4 + 2 = 7 45 + 28 = 73
22+14+8
The patterns and properties to compute mentally 120 times 30 is the numbers 12 and 3 plus the two 0. Multiply 12 by 3 (36) and add the two 0 (3600).
Back in the day, regrouping in addition was called "carrying" and regrouping in subtraction was called "borrowing." I think "regrouping" is a better term for all of it. These problems might be easier to visualize if you copy them vertically. Example: 56 - 39 Just looking at it, you might think there's a problem with subtracting nine from six until you realize that 56 is 5 tens and 6 ones which is the same thing as 4 tens and 16 ones. Now you can subtract 9 from 16, leaving 7 in the ones place and 3 from 4, (the regrouped 5) leaving 1 in the tens place. 56 - 39 = 17 Example: 45 + 28 5 + 8 is 13, which won't fit in the ones place, so we leave 3 of the ones there and regroup the ten other ones into one ten which we add in the tens column. 1 + 4 + 2 = 7 45 + 28 = 73
"Regrouping" is a more modern word for "borrowing". When subtracting with decimals, if you are trying to subtract a larger digit from a smaller digit, you "regroup" the next digit to the left by taking one away from it and adding 10 to the number you are subtracting from. Example 84 - 19 _____ You can't subtract 9 from 4, so you take one away from the next digit over (the 8) and add 10 to the 4. 14 - 9 is 5 in the ones digits 7 - 1 is 6 in the tens digits Now if you are subtracting mixed numbers, the regrouping process is essentially the same, except that instead of always regrouping by tens, we regroup by the denominator size. 8 1/5 - 3 3/5 ______ We can't subtract 3/5 from 1/5, so we regroup one unit from the 8 into 5 fifths. 7 6/5 -3 3/5 _______ 4 3/5 It is very easy when you get some practice doing it.
2
If Bill says that he can add 23 and 40 without regrouping he is correct. Both numbers can easily be added in your head.
7 7/12 plus 3 8/9
you take away one of the whole number=then you add or subtract your fractions=
What is the answer for 8 1/3 - 5 2/6
No colour
The problem of adding 23 and 40 is trivial. Since 2 + 4 = 6, we add the tens column and get 60; there is only 3 in the ones column so the answer is 63.
the purpose of this invention is to help add up numbers. It's quicker and easier to do instead of mentally trying to calculate the numbers by hand.(: your welcome
I take this question to mean what number when added to 457 will yield 999. In this case it is 542.
the property says that a+b+c is the same as a+c+b and it is the commutative property of addition.
460
Back in the day, regrouping in addition was called "carrying" and regrouping in subtraction was called "borrowing." I think "regrouping" is a better term for all of it. This problem might be easier to visualize if you copy it vertically. Example: 45 + 28 5 + 8 is 13, which won't fit in the ones place, so we leave 3 of the ones there and regroup the ten other ones into one ten which we add in the tens column. 1 + 4 + 2 = 7 45 + 28 = 73