(x-5)(x+11)
X2 + 4xx(x + 4)=======
-x2 + 6x + 16 = -(x2 - 6x - 16) = -(x - 8)(x + 2) = -(8 - x)(x + 2)
x2 + 6x + 8 = (x + 4)(x + 2)
x3 + x2 - 6x + 4 = (x - 1)(x2 + 2x - 4)
x2 + 6x + 9 = 81 x2 + 6x = 72 x2 + 6x - 72 = 0 (x+12)(x-6) = 0 x= -12, 6 (two solutions)
This is a quadratic equation question in finding the possible values of x x2 - 6x = - 8 x2 - 6x + 8 = 0 Factorise the expression in the equation: (x-2)(x-4) = 0 Therefore: x = 2 or x = 4
4(x2 + 4)
x(x+5)
x2 + 6x + 5 can be factored into (x+1) (x+5)
324
(x+5)(x+3)