X2 - 6X + 27 = 0 what are the factors of 27 that add to - 6? None! This polynomial is unreal and does not intersect the X axis.
please help on this x2+6x+27=
x2 +6x = 27 x2 + 6x - 27 = 0 x2 + 9x - 3x - 27 = 0 x(x + 9) - 3(x + 9) =0 (x - 3)(x + 9) = 0 So x can equal 3 or -9.
With great difficulty not knowing if 6x and 27 are plus or minus
x2 + 6x - 27 = (x + 9)(x - 3)
x2 + 6x = x*(x + 6)
-x2 + 6x + 16 = -(x2 - 6x - 16) = -(x - 8)(x + 2) = -(8 - x)(x + 2)
x2 + 6x + 8 = (x + 4)(x + 2)
x3 + x2 - 6x + 4 = (x - 1)(x2 + 2x - 4)
x2-6x-27 = (x+3)(x-9) when factored
x2 + 6x + 9 = 81 x2 + 6x = 72 x2 + 6x - 72 = 0 (x+12)(x-6) = 0 x= -12, 6 (two solutions)
x2 + 6x + 5 can be factored into (x+1) (x+5)