How would you prove algebraically that the function: f(x)= |x-2|, x<= 2 , is one to one?
Expressed algebraically, this is equal to 52 + x.
Expressed algebraically, d + 7d = 8d.
Expressed algebraically, this is equal to x - 92.
This is present perfect continuous. They have been proving themselves very helpful.
ALGEBRAICALLY : by means of ALGEBRA
Algebraically zero
Algebraically, a times 2 is 2a.
Yes they can. For example: if I have the fraction 3/6, this equals out to 1/2 or 0.5. Another fraction, for example 4/8, when you divide the numerator and the denominator by 4, you also get 1/2 or 0.5. Another way to do this is to get out a calculator, and punch in 3/6. You should get 0.5 as your answer. Then punch in 4/8, and you should still get the answer 0.5 proving that two different fractions can have the same equivalent.
Expressed algebraically, this is equal to 9t.
You get the exact solution.
How would you prove algebraically that the following function is one to one? f(x)= (x+3)^2 , x>= -3?
The first step not possible in solving an equation algebraically is not to provide an equation in the first place in which it appears to be so in this case.
Expressed algebraically, this is equal to x/2.
Expressed algebraically, this is equal to 4/x.
Expressed algebraically, this is equal to 700/x.
Is it E=mc2?