To prove fractions algebraically, you typically show that two fractions are equivalent by manipulating their numerators and denominators using algebraic operations. This can involve cross-multiplying to check if the products are equal or simplifying both fractions to a common form. Additionally, you can use properties of equality and arithmetic operations to demonstrate that the fractions yield the same value. Ultimately, the goal is to establish a clear relationship between the two fractions through algebraic reasoning.
How would you prove algebraically that the function: f(x)= |x-2|, x<= 2 , is one to one?
Expressed algebraically, d + 7d = 8d.
Expressed algebraically, this is equal to x - 92.
Expressed algebraically, this is equal to 52 + x.
This is present perfect continuous. They have been proving themselves very helpful.
ALGEBRAICALLY : by means of ALGEBRA
Algebraically zero
Algebraically, a times 2 is 2a.
Yes they can. For example: if I have the fraction 3/6, this equals out to 1/2 or 0.5. Another fraction, for example 4/8, when you divide the numerator and the denominator by 4, you also get 1/2 or 0.5. Another way to do this is to get out a calculator, and punch in 3/6. You should get 0.5 as your answer. Then punch in 4/8, and you should still get the answer 0.5 proving that two different fractions can have the same equivalent.
You get the exact solution.
Expressed algebraically, this is equal to 9t.
How would you prove algebraically that the following function is one to one? f(x)= (x+3)^2 , x>= -3?
The first step not possible in solving an equation algebraically is not to provide an equation in the first place in which it appears to be so in this case.
Expressed algebraically, this is equal to 4/x.
Expressed algebraically, this is equal to 700/x.
Expressed algebraically, this is equal to x/2.
Is it E=mc2?