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In a quadratic equation, one with order two, in the form of ax2 + bx + c = 0, the solution for x is (-b +/- squareroot (b2 - 4ac)) / 2a. Note: The term b2 - 4ac is known as the discriminant. If it is positive, then there are two real solutions. If it is zero, then there is one real solution. If it is negative, then there are two imaginary solutions, also known as complex conjugates. To visualize this, consider that the original equation is a parabola. If its zero-slope point (apex) touches the x-axis, there is one real root. If it crosses the x-axis, there are two real roots. If it does not cross the x-axis, there are two complex roots.
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How do you solve x 52 x - 22 37 using the quadratic formula?
With great difficulty because it is not a quadratic equation or even a quadratic expression.
How do you solve 0 equals x squared minus ten x plus 16?
Solve using the quadratic formula
Solve this quadratic equation using the quadratic formula?
For any quadratic ax2 + bx + c = 0 we can find x by using the quadratic formulae: the quadratic formula is... [-b +- sqrt(b2 - 4(a)(c)) ] / 2a
What is a solution of a quadratic?
A quadratic function is ax2+bx+c You can solve for x by using the quadratic formula, which, as the formula requires the use of square roots, would be tricky to put here.
X plus 5 squared plus x - 2 squared 37 solve using the quadratic formula?
You can't because it is not a quadratic equation.
