To calculate the outside diameter of a steel coil, you first need to determine the inside diameter (ID) and the thickness of the steel material. The outside diameter (OD) can then be calculated using the formula: OD = ID + 2 × thickness. If the coil is wound in layers, you may also need to account for the number of layers by adding the thickness multiplied by the number of layers to the ID.
To calculate the outer diameter of a steel coil, you can use the formula: ( D = \frac{(L \times 1000)}{(\pi \times t)} + t ), where ( D ) is the outer diameter, ( L ) is the length of the steel strip in meters, and ( t ) is the thickness of the steel strip in millimeters. The term ( \pi ) (approximately 3.14159) is used to account for the circumference of the coil. This formula accounts for the thickness of the coil, which adds to the diameter.
L = length of coil D = diameter of coil N = number of turns P = pitch L^2 = (pi*D*N)^2 + (P*N)^2 using AUTOCAD make sure view mode in isometric - type command HELIX - input base diameter - input top diameter - right click mouse, select turn height - input turn height (pitch) - input height of coil you can see length of coil by clicking picture twice to see length in property of helix the different result between formula above and using autocad is 0.23 %
The length of one coil can vary significantly depending on the diameter and spacing of the coil. For instance, a coil of wire with a diameter of 1 meter and 10 turns would have a length of approximately 3.14 meters (using the formula for the circumference of a circle, ( C = \pi \times d )). To determine the exact length of a specific coil, you would need to know its dimensions.
Lay length is calculated by measuring the distance a rope or cable extends when laid out flat, typically from one end to the other. If you know the diameter of the coil or spool and the number of turns, you can use the formula: Lay Length = (Number of Turns x Diameter of Coil) / π. Alternatively, for ropes with a specific lay pattern, you may need to measure the angle of the lay and apply trigonometric principles.
COOLING COIL CONDENSATE CAN BE CALCULATED BY THE FOLLOWING FORMULA" CC CONDENSATE (GPM)=(4.5/500)*CFM*CHANGE IN HUMIDITY RATIO OF THE AIR(LB/MOISTER/LB OF DRY AIR)
you have to measure the diameter of the coil and then multiply the diamter by pi
To calculate the outer diameter of a steel coil, you can use the formula: ( D = \frac{(L \times 1000)}{(\pi \times t)} + t ), where ( D ) is the outer diameter, ( L ) is the length of the steel strip in meters, and ( t ) is the thickness of the steel strip in millimeters. The term ( \pi ) (approximately 3.14159) is used to account for the circumference of the coil. This formula accounts for the thickness of the coil, which adds to the diameter.
You're essentially trying to calculate the diameter of a cylinder with a hole in the middle. There are two formulas for volume which you need. Volume= Pi * r2 * h (where Pi=3.142, r = radius of the coil, h = width of the coil) Volume= Weight/Density Since both these formula equal Volume: Weight/Density= Pi * r2 * h Since the weight you have is for a cylinder with a hole in it, you need to calculate the volume of the whole cylinder (without the hole) and subtract the volume of the hole. So for a steel coil Weight/Density = (Pi * rc2 * h)-(Pi * rh2 * h) where rc= the radius of the coil and rh = the radius of the hole (Radius=diameter/2) you're trying to calculate the radius of the coil, so rearrange the formula to get: ((Weight/Density)/Pi*h) + rh2 = rc2 The diameter of the coil = 2 *rc NOTE:- It's important to keep your units of measure consistent throughout the calculation. Density is generally represented by kilograms per cubic metre (kg/m3) - for us metric users ;-) Therefore keep your coil weight in kgs and your radius / width measures in metres.
You know that each 'wrap' or turn of wire in the coil has to go all the way around the coil-form, and you know how to calculate the distance around a circle. So all you have to do is count the number of times the wire goes around the coil, measure the coil's diameter, calculate its circumference, and multiply that by the number of turns in the coil.
kg = 6.16546 x width mm x OD2 x bore2 ---- 1000000
It is put there to help prevent wear from vibration.
Weight divided by 3.399, divided by gauge. Divided by width.
0.7854*r*r*h where r- radius of coil h is height of coil for 3" coil volume is 0.7854*1.5*1.5*2.54*2.54*1.7/10000=2lts
density=mass/volume 7.850=2500kg/(0.47*L*0.914) Ravindra
The diameter of the coil affects the amount of electricity as longer the coil longer the electricity.
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The diameter of a spring coil does not directly affect the force constant of the spring. The force constant is primarily determined by the material of the spring and the number of coils. However, a larger diameter may result in a softer spring with more flexibility.