g(t) = 2/t
The function is the same as writing g(t) = 2 t-1,
and that's not too difficult to differentiate:
g'(t) = -2 t-2
g'(1/2) = -2 (1/2)-2 = -2 (4) = -8
1 divided by x to the third power equals x to the negative third. The derivative of x to the negative third is minus three x to the negative fourth.
The "critical points" of a function are the points at which the derivative equals zero or the derivative is undefined. To find the critical points, you first find the derivative of the function. You then set that derivative equal to zero. Any values at which the derivative equals zero are "critical points". You then determine if the derivative is ever undefined at a point (for example, because the denominator of a fraction is equal to zero at that point). Any such points are also called "critical points". In essence, the critical points are the relative minima or maxima of a function (where the graph of the function reverses direction) and can be easily determined by visually examining the graph.
Yes.
pi divided by 6 is a constant and so its first derivative is 0. And since that is also a constant, the second derivative is 0. It is not clear what f(x) = csc(x) has to do with that!
Yes, the derivative of xi with respect to x equals i. Is that what you were trying to ask?
you have to first find the derivative of the original function. You then make the derivative equal to zero and solve for x.
Because the derivative of e^x is e^x (the original function back again). This is the only function that has this behavior.
Following the correct order of operations: derivative of x^2 + 6/2 = derivative of x^2 +3, which equals 2x
1 divided by x to the third power equals x to the negative third. The derivative of x to the negative third is minus three x to the negative fourth.
The "critical points" of a function are the points at which the derivative equals zero or the derivative is undefined. To find the critical points, you first find the derivative of the function. You then set that derivative equal to zero. Any values at which the derivative equals zero are "critical points". You then determine if the derivative is ever undefined at a point (for example, because the denominator of a fraction is equal to zero at that point). Any such points are also called "critical points". In essence, the critical points are the relative minima or maxima of a function (where the graph of the function reverses direction) and can be easily determined by visually examining the graph.
Yes.
pi divided by 6 is a constant and so its first derivative is 0. And since that is also a constant, the second derivative is 0. It is not clear what f(x) = csc(x) has to do with that!
Yes, the derivative of xi with respect to x equals i. Is that what you were trying to ask?
True
In this case, you'll need to apply the chain rule, first taking the derivative of the tan function, and multiplying by the derivative of 3x: y = tan(3x) ∴ dy/dx = 3sec2(3x)
13
Total annual income divided by 12 equals 1 month pay To compute annual income.... For hourly paid....at full time (40 hours a week) Hourly rate times 2080 hours equals annual payFor Salary on biweekly... salary times 26 equals annual pay