you can convert Fermat's equation into a system.
Assuming z^3=x^3+y^3.
Mean
[z(z+1)/2]^2 - [1^3+2^3+3^3+4^3+5^3+6^3+7^3+....+(a-1)^3+(a+1)^3+.......+z^3]+[z(z+1)/2]^2 - [1^3+2^3+3^3+4^3+5^3+6^3+7^3+....+(a-1)^3+(a+1)^3+.......+x^3+y^3]=[x(x+1)/2]^2 - [1^3+2^3+3^3+4^3+5^3+6^3+7^3+....+(a-1)^3+(a+1)^3+......+x^3]+[y(y+1)/2]^2 - [1^3+2^3+3^3+4^3+5^3+6^3+7^3+....+(a-1)^3+(a+1)^3+.......+y^3]
after simple, x^3 and y^3 have been lost , just rest z^3.
number (a) can change unlimited
This complex system have no solution integer.
whats the equation to convert meters to inches?
1. using convert one system of units in to another system. 2. check the correctness of an equation 3. to know the relation between physical quantities in a given equation
Solve it for 'y' .
Kelvin = Celsius + 273.15
Use this equation to convert Celsius to Rankine: ºR = (ºC x 1.8) + 491.67
whats the equation to convert meters to inches?
1. using convert one system of units in to another system. 2. check the correctness of an equation 3. to know the relation between physical quantities in a given equation
Solve the equation for ' y '.
hoe do you convert household system?
You can take the logarithm on both sides of an equation. The real trick is to figure out when this will help you to solve the equation, and when not.
It depends on what you need to convert.
Kelvin = Celsius + 273.15
Solve it for 'y' .
Use this equation to convert degrees Fahrenheit to Kelvin: [K] = ([°F] + 459.67) × 0.556
To convert from Kelvin to Celsius, subtract 273.15 from the Kelvin temperature. 389 K - 273.15 = 115.85 degrees Celsius. So, 389 Kelvin is equivalent to 115.85 degrees Celsius.
Use this equation to convert Celsius/Centigrade to degrees Kelvin: [K] = [°C] + 273.15
Use this equation to convert Celsius to Rankine: ºR = (ºC x 1.8) + 491.67