To convert from km²/h² to m²/s², you can use the conversion factors for kilometers to meters and hours to seconds. Since 1 km = 1,000 m, you square this conversion factor for area, resulting in (1 \text{ km}^2 = (1,000 \text{ m})^2 = 1,000,000 \text{ m}^2). For time, since 1 hour = 3600 seconds, you square this as well, giving (1 \text{ h}^2 = (3600 \text{ s})^2 = 12,960,000 \text{ s}^2). Therefore, to convert km²/h² to m²/s², multiply by (\frac{1,000,000}{12,960,000}), or approximately (0.0771605).
8pi m2 ~ 25.1327412 m2
Surface area = 2*(L*B + B*H + H*L) = 2*(4*5 + 5*8 + 8*4) = 2*(20 + 40 + 32) = 2*92 = 184 m2
To convert a quadratic equation from vertex form, (y = a(x - h)^2 + k), to standard form, (y = ax^2 + bx + c), you need to expand the equation. Start by squaring the binomial: ( (x - h)^2 = x^2 - 2hx + h^2 ). Then, multiply by (a) and add (k) to obtain (y = ax^2 - 2ahx + (ah^2 + k)), where (b = -2ah) and (c = ah^2 + k). This results in the standard form of the quadratic equation.
To convert a vertex form equation of a parabola, given as ( y = a(x - h)^2 + k ), to standard form ( y = ax^2 + bx + c ), expand the squared term: ( (x - h)^2 = x^2 - 2hx + h^2 ). Then, multiply through by ( a ) and combine like terms: ( y = ax^2 - 2ahx + (ah^2 + k) ). The coefficients ( a ), ( b = -2ah ), and ( c = ah^2 + k ) represent the standard form parameters.
f(x) = x/2Then the differential is lim h->0 [f(x+h) - f(x)]/h= lim h->0 [(x+h)/2 - x/2]/h= lim h->0 [h/2]/h= lim h->0 [1/2] = 1/2f(x) = x/2Then the differential is lim h->0 [f(x+h) - f(x)]/h= lim h->0 [(x+h)/2 - x/2]/h= lim h->0 [h/2]/h= lim h->0 [1/2] = 1/2f(x) = x/2Then the differential is lim h->0 [f(x+h) - f(x)]/h= lim h->0 [(x+h)/2 - x/2]/h= lim h->0 [h/2]/h= lim h->0 [1/2] = 1/2f(x) = x/2Then the differential is lim h->0 [f(x+h) - f(x)]/h= lim h->0 [(x+h)/2 - x/2]/h= lim h->0 [h/2]/h= lim h->0 [1/2] = 1/2
8pi m2 ~ 25.1327412 m2
A = .5*h*b = 36 m2 h = 2b substitute for h in the first equation with the second equation: .5*(2b)*b = 36 m2 b2 = 36 m2 b = 6 m
The formula for the area of a triangle is A = 1/2b x h. A = 1/2*18m*20m = 180 m2
Surface area = 2*(L*W + W*H + H*L) = 324 m2
Surface area = 2*(L*B + B*H + H*L) = 2*(4*5 + 5*8 + 8*4) = 2*(20 + 40 + 32) = 2*92 = 184 m2
Combining these parts we get the formula: area = 2 π r 2 + 2 π r h where: π is Pi, approximately 3.142 r is the radius of the cylinder h height of the cylinder For a detailed look at how this formula is derived
To convert a quadratic equation from vertex form, (y = a(x - h)^2 + k), to standard form, (y = ax^2 + bx + c), you need to expand the equation. Start by squaring the binomial: ( (x - h)^2 = x^2 - 2hx + h^2 ). Then, multiply by (a) and add (k) to obtain (y = ax^2 - 2ahx + (ah^2 + k)), where (b = -2ah) and (c = ah^2 + k). This results in the standard form of the quadratic equation.
A=b*h area = base (times) height P=2b + 2h perimeter = 2 (times) base (plus) 2 ( times) height A= b*h 12 = b*h 12/b = h let x = b h = 12/x since x = b and h = 12/x therefore P = 2x + 2(12/x)
Measure the radius and height of the cylinder in feet (or other units and then convert). Total surface area = 2*pi*r2 + 2*pi*r*h = 2*pi*r*(r+h) square feet.
To calculate the volume of a pool in cubic meters, you can use the formula for the volume of a cylinder: V = πr^2h, where r is the radius and h is the height. Convert the diameter to radius by dividing by 2 (224 cm / 2 = 112 cm). Then, plug in the values: V = π * (112 cm)^2 * 76 cm. After calculating, convert the result to cubic meters (1 m^3 = 1,000,000 cm^3).
1207 km/h
38.5 h