y = x2 + 3/sqrt(x) = x2 + 3*x-1/2 dy/dx = 2x + 3*(-1/2)*x-3/2 = 2x - 3/2*x-3/2
dy/dx = a
d/dx(x + 2) = d/dx(x) + d/dx(2) = 1 + 0 = 1
d/dx (3x+25)=3
d/dx(cos x) = -sinx
y = x2 + 3/sqrt(x) = x2 + 3*x-1/2 dy/dx = 2x + 3*(-1/2)*x-3/2 = 2x - 3/2*x-3/2
y = 6*x1/2 - 3x dy/dx = 6*(1/2)*x-1/2 - 3 = 3x-1/2 - 3 = 3/sqrt(x) - 3 or 3[1/sqrt(x) - 1]
dy/dx = a
d/dx(x + 2) = d/dx(x) + d/dx(2) = 1 + 0 = 1
You have to differentiate the equation. The dy/dx is the slope.
d/dx (3x+25)=3
log 3 is a constant, so d/dx log3, like d/dx of any constant, equals zero.
d/dx(cos x) = -sinx
x = yy differentiate both sides with respect to x dx = (y * yy-1) dy dy/dx = y * yy-1 dy/dx = yy = x hence differentiate of y wrt x is x only
There is no equation or inequality in the question that can be solved! There is an expression but expressions cannot be solved.
y=x3+ 2x, dx/dt=5, x=2, dy/dt=? Differentiate the equation with respect to t. dy/dt=3x2*dx/dt Substitute in known values. dy/dt=3(2)2 * (5) dy/dt=60
dy/dx = 3 integral = (3x^2)/2