4(x + 2)(x + 2)
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b. -4x2+20 = 4x2 = 4-20x2 = -16x = -4Note that -42 = -16 but (-4)2 in brackets = 16
The Commutative Property of Addition.
4x2 - 20x + 16 = 4(x2 - 5x + 4) = 4(x - 1)(x - 4)
4x - 8 = 0 when x = 2 Substitute this value of x in 16x3 + 4x2 - 144 to give 16*8 + 4*4 - 144 = 128 + 16 - 144 = 144 - 144 = 0 So, by the remainder theorem, (x-2) is a factor of 16x3 + 4x2 - 144 Also, the coeffs are all divisibl by 4 so 4 is also a factor (x-2) is a factor, 4 is a factor so 4*(x-2) = (4x - 8) is a factor.
to factor (x2-16x+64), you need to find two number whose product is 64 and whose sum is 16. These two numbers are 8 and 8. (x2-16x+64)=(x-8)(x-8)