b. -4x2+20 = 4x2 = 4-20x2 = -16x = -4Note that -42 = -16 but (-4)2 in brackets = 16
The Commutative Property of Addition.
4x2 - 20x + 16 = 4(x2 - 5x + 4) = 4(x - 1)(x - 4)
4x - 8 = 0 when x = 2 Substitute this value of x in 16x3 + 4x2 - 144 to give 16*8 + 4*4 - 144 = 128 + 16 - 144 = 144 - 144 = 0 So, by the remainder theorem, (x-2) is a factor of 16x3 + 4x2 - 144 Also, the coeffs are all divisibl by 4 so 4 is also a factor (x-2) is a factor, 4 is a factor so 4*(x-2) = (4x - 8) is a factor.
to factor (x2-16x+64), you need to find two number whose product is 64 and whose sum is 16. These two numbers are 8 and 8. (x2-16x+64)=(x-8)(x-8)
It is; (2x+4)^2.
x3 + 4x2 + 16x + 64 =x2*(x + 4) + 16(x + 4) = (x + 4)*(x2 + 16) which has no further real factors.
If your function is 4x^2+16x+16=0 then x=-2, if it is 4x^2-16x+16=0, then x=2
True
b. -4x2+20 = 4x2 = 4-20x2 = -16x = -4Note that -42 = -16 but (-4)2 in brackets = 16
The Commutative Property of Addition.
4x2 - 20x + 16 = 4(x2 - 5x + 4) = 4(x - 1)(x - 4)
16 - a2
4x - 8 = 0 when x = 2 Substitute this value of x in 16x3 + 4x2 - 144 to give 16*8 + 4*4 - 144 = 128 + 16 - 144 = 144 - 144 = 0 So, by the remainder theorem, (x-2) is a factor of 16x3 + 4x2 - 144 Also, the coeffs are all divisibl by 4 so 4 is also a factor (x-2) is a factor, 4 is a factor so 4*(x-2) = (4x - 8) is a factor.
to factor (x2-16x+64), you need to find two number whose product is 64 and whose sum is 16. These two numbers are 8 and 8. (x2-16x+64)=(x-8)(x-8)
The GCF is 8.
First you need to solve for y. So write 4x2+y=16 so y=16-4x2 Now write f(x)=16-4x2