Q: How do you factor 4x2 plus 8x plus 32?

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(2x - 1)(2x + 5)

4(x^2 + 2x - 5)

No, it has factors... 4x2 + 8x -21 = (2x+7)(2x-3)

ANSWER: -4X2 -8X-4x (x+2)= (-4x * x) + (-4x*2)= -4X2 -8X

4(x^2 + 8x + 160)

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(2x - 1)(2x + 5)

4(x + 1)(x + 1)

(2x + 5)(4x2 - 10x + 25)

4(x^2 + 2x - 5)

No, it has factors... 4x2 + 8x -21 = (2x+7)(2x-3)

If that's + 4x2, the answer is 2x(x2 + 2x - 4)

3x-3x+4x^2+8x=4x^2+8x

ANSWER: -4X2 -8X-4x (x+2)= (-4x * x) + (-4x*2)= -4X2 -8X

(4x2) (x/4)(8x - 32) =x3(8x - 32) = 8x3(x - 4)

x2 - 8x + 32 = 0 (assuming)you can factor or use the quadratic equation.I recommend the quadratic equation.

4x2 + 8x + 4 = 4 (x2 + 2x + 1) = 4 (x + 1)2

This is how I did it:8x3+4x2+6x+3[8x3+4x2]+[6x+3][(4x2)(2x+1)]+[(3)(2x+1)]....as you can see, this is in the general form of ab+cb, which factored is b(a+c), so:(2x+1)(4x2+3)