a2 - 4a + 4
a2 + 12a + 27 = (a + 3)(a + 9)
a2(2a2-21a+49) a2(2a-7)(a-7)
Umm should be something like this... 5a3b2 + 15a2b2 + 5ab2 = 5ab2[(a2) + (3a) + 1] there you are factorised!
2a3-16a2+30a Factor out 2a: 2a(a2-8a+15) (2a)(a-5)(a-3) This is the most factored form of this expression.
( a2 ) ( a2+1 )
a2 - 4a + 4
a2+9a+20 = (a+4)(a+5) when factored
(a2+2b2-2ab)(a2+2b2+2ab)
It is: (a+1)(a+3) when factored
a2 + 12a + 27 = (a + 3)(a + 9)
(a+b+c) (a+b-c)
a2(2a2-21a+49) a2(2a-7)(a-7)
a2 + 28a + 27 = 0 (a + 1)(a + 27) = 0 a = -1 or -27 However, the second line is the factorised form, the third is what a is equal to
(a2 + 2a + 1)/(5a + 5)factor, top and bottom(a + 1)(a + 1)/5(a + 1)cancel an (a + 1) top and bottom= (a + 1)/5=========
(a2 + a + a2) = (2a2 + a) = a (2a + 1)
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: -2 plus or minus the square root of 58. a = 5.6157731058863909 a = -9.615773105863909