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Anonymous
(a + 9)(a - 3)
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a2 - 4a + 4
a2 + 12a + 27 = (a + 3)(a + 9)
a2(2a2-21a+49) a2(2a-7)(a-7)
Umm should be something like this... 5a3b2 + 15a2b2 + 5ab2 = 5ab2[(a2) + (3a) + 1] there you are factorised!
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