It is -20 + 11t. Its numerical value will depend on the value of t, which is not disclosed.
T(t + 4)
(t + 7)(t - 1)
-10
If f(t) = t5 + t4 + t3 + t2 + t + 1 then remainder when divided by t+1 is f(-1) The remainder is, therefore, (-1)5 + (-1)4 + (-1)3 + (-1)2 + (-1) + 1 = -1 + 1 - 1 + 1 - 1 + 1 = 0
It is -20 + 11t. Its numerical value will depend on the value of t, which is not disclosed.
Rearrange as: 2t2+11t+12 = (2t+3)(t+4) when factored
(t + 7)(2t - 3)
t2 - 59t + 54 - 82t2 + 60t = - 81t2 + t + 54
8t^2 - 11t - 4
T(t + 4)
t2 + 3t - 10
(t - 7)(t - 11)
(t + 7)(t - 1)
4(t + 3)(t2 - 3t + 9)
We have to trust the equation you give us, telling us that the acceleration of gravity is 9.8,the tossing speed is 20 straight up, and the stone leaves your hand from 10 aboveground.If all of that is true, then H = -4.9 t2 + 20t + 10, and when the stone hits the ground,-4.9 t2 + 20t + 10 = 0Multiply both sides of the equation by -1 :4.9 t2 - 20t - 10 = 0We're not going to be able to factor that ugly thing,so we have to use the quadratic equation:t = [ 20 +/- sqrt(400 + 196) ] / 9.8 = ( 20 +/- 24.413) / 9.8I get 4.532 seconds (rounded)
yes