(x^2 - 4)(x^2 + 9)
set to zero to see roots ( watch out for the surprise! )
2m^2 - 8 -First you should factor out a two. --> 2(m^2-4) -You now have something squared minus something else squared; You have m squared minus 2 squared. Whenever you have something squared minus something squared as you do in this case, there is a simple rule to remember: You can reduce that expression into the quantity of the square root of the first number or variable plus the square root of the second number or variable Times the quantity of the square root of the first number or variable minus the second number or variable squared. --> In the case of your expression: ----> 2(m+2)(m-2)<-----
Without an "equals" word or sign somewhere, there is nothing to solve.You only have an expression, not an equation.
The value of that expression depends on the value of "x". You can't really simplify it, except that you can factor it by separating the common factor "x".
2
x³ - x² + x - 3 (x² + 1)(x - 1) - 2
(3 - i)(3 + i)
Without that other number, all you've got is zero.
(x + 6)(x - 6)
x^2 - y^2 - 4 is in its simplest form.
x2-81 = (x-9)(x+9)
(x - 2)(2x - 3)
2m^2 - 8 -First you should factor out a two. --> 2(m^2-4) -You now have something squared minus something else squared; You have m squared minus 2 squared. Whenever you have something squared minus something squared as you do in this case, there is a simple rule to remember: You can reduce that expression into the quantity of the square root of the first number or variable plus the square root of the second number or variable Times the quantity of the square root of the first number or variable minus the second number or variable squared. --> In the case of your expression: ----> 2(m+2)(m-2)<-----
The expression x2 + 1x - 12 can be factored out as (x - 3)(x + 4)
3x squared minus 25x minus 28
Without an "equals" word or sign somewhere, there is nothing to solve.You only have an expression, not an equation.
The value of that expression depends on the value of "x". You can't really simplify it, except that you can factor it by separating the common factor "x".
An algebraic expression