An algebraic expression
(b-c)(a+b)-ac
By factoring I get x-3 divided by x+3
he made the theorem C squared = A squared + B squared and A squared = C squared - B squared or B squared = C squared - A squared
xsquared minus x minus 72
0x-x=0
B squared equals c squared minus a squared then to find B take the square root of you answer for b squared
The expression "a squared b squared minus c squared" can be mathematically represented as ( (ab)^2 - c^2 ). This can be factored using the difference of squares formula, which states that ( x^2 - y^2 = (x - y)(x + y) ). Thus, it can be factored as ( (ab - c)(ab + c) ).
3c(squared)-17c-6 = 0 (3c+1)(c-6) = 0 c= negative one third or positive 6
n2 - 100 = (n + 10)(n - 10)
It is: (c-4)(c-8) when factored
(b-c)(a+b)-ac
100 minus 4 = 96
It is: (B -10)(B +10) when factored
If your Problem is organized like this: A x squared plus B x plus C, the equation is: (B plus or minus the square root of(B squared minus 4 A C)) over 2A
How about: (3 squared minus 2 cubed) + 1 to the fourth 3 cubed minus 5 squared log 100 Kim Basinger's weeks minus Doris Day's cents.
3x squared minus 25x minus 28
2x squared minus 4