Factor: x3 - 12x2 + 35x 1. Factor out a x: x(x2 - 12x + 35). 2. Factor x2 - 12x + 35 which is (x-5)(x-7). 3. Answer: x(x-5)(x-7).
(x - 1)(x^2 - 5)
x3 + 12x2 + 48x + 64= (x + 4)(x2 + 8x + 16)= (x + 4)(x + 4)(x + 4)= (x + 4)3
Factor out an X X(X^2 - 12X + 35) factor quadratic equation X(X - 7)(X - 5) ------------------- fully factored
x^3+5x^2+6xFirst take out an x: x(x^2+5x +6)Then find the roots: x(x+2)(x+3)
x3 + 12x2 - 5x = x(x2 + 12x - 5) = x(x + 6 - √41)(x + 6 + √41)
5x is a common factor of all terms:- 5x(x3+4x2+9)
Factor: x3 - 12x2 + 35x 1. Factor out a x: x(x2 - 12x + 35). 2. Factor x2 - 12x + 35 which is (x-5)(x-7). 3. Answer: x(x-5)(x-7).
(x - 1)(x^2 - 5)
x3 - 12x2 + 35x = x (x2 - 12x + 35) = x (x - 7) (x - 5)
x3 + 12x2 + 48x + 64= (x + 4)(x2 + 8x + 16)= (x + 4)(x + 4)(x + 4)= (x + 4)3
x3 + 2x2 + 5x + 4 = (x + 1)(x2 + x + 4)
2x3 - 7 + 5x - x3 + 3x - x3 = 8x - 7
(x - 1)(x^2 - 5x + 2)
Factor out an X X(X^2 - 12X + 35) factor quadratic equation X(X - 7)(X - 5) ------------------- fully factored
x3 + 3x2 - 6x - 8 = (x - 2)(x2 + 5x + 4) = (x - 2)(x + 1)(x + 4)
x^3+5x^2+6xFirst take out an x: x(x^2+5x +6)Then find the roots: x(x+2)(x+3)