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How do you solve equations x3 plus 5x2 equals 6x?
your equation is this... x3 + 5x2 = 6x get all the terms on the left side x3 + 5x2 - 6x = 0 now factor out an "x" x(x2 + 5x - 6) = 0 now factor the equation inside x(x + 6)(x - 1) from this you can find your x-values x= 0, -6, and 1 now that you have your x-values your equation is solved. just use algebra to get all of the terms on the one side. then factor out anything that is common in all of the terms. then factor the polynomial. then find what values for "x" that satisfy the equation.
How do you solve x3 plus 4x2 plus 6x plus 24?
x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)
How do you factor x3 plus 5x2 minus 16x minus 80?
To factorise x3 + 5x2 - 16x - 80 I note that -80 = 5 x -16 and 5 & -16 are the coefficients of x2 and x. Thus I have: x3 + 5x2 - 16x - 80 = (x + 5)(x2 - 16) and the second term is a difference of 2 squares, meaning I have: x3 + 5x2 - 16x - 80 = (x + 5)(x + 4)(x - 4)
X3 plus x2 minus 6x plus 4?
x3 + x2 - 6x + 4 = (x - 1)(x2 + 2x - 4)
How do you factor x3 - 5x2 8x -4?
(x - 2)(x - 2)(x - 1)
How do you solve equations x3 plus 5x2 equals 6x?
your equation is this... x3 + 5x2 = 6x get all the terms on the left side x3 + 5x2 - 6x = 0 now factor out an "x" x(x2 + 5x - 6) = 0 now factor the equation inside x(x + 6)(x - 1) from this you can find your x-values x= 0, -6, and 1 now that you have your x-values your equation is solved. just use algebra to get all of the terms on the one side. then factor out anything that is common in all of the terms. then factor the polynomial. then find what values for "x" that satisfy the equation.
How do you factor x³ plus 5x² plus 6x?
(x3+5x2+6x)/x to get x(x2+5x+6) find numbers that multiply to 6 and add to five (2 and 3) your factors are x, x+2, and x+3
Factor the polynomial of x3 plus 5x2 - x - 5?
x3 + 5x2 - x - 5 = (x2 - 1)(x + 5) = (x + 1)(x - 1)(x + 5)
What are the factors of 3x3 plus 5x2-6x-10?
(3x + 5)(x2 - 2)
2x3 - 7 plus 5x2 - x3 plus 3x - x3?
2x3 - 7 + 5x - x3 + 3x - x3 = 8x - 7
Factor x3 plus 3x2-6x-8?
x3 + 3x2 - 6x - 8 = (x - 2)(x2 + 5x + 4) = (x - 2)(x + 1)(x + 4)
How do you solve x3 plus 4x2 plus 6x plus 24?
x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)
When dividing the polynomial x3 plus 5x2 plus 7x plus 3 by x plus 3 the remainder is 0 making x plus 3 a factor?
True.
How do you factor x3 plus 5x2 minus 16x minus 80?
To factorise x3 + 5x2 - 16x - 80 I note that -80 = 5 x -16 and 5 & -16 are the coefficients of x2 and x. Thus I have: x3 + 5x2 - 16x - 80 = (x + 5)(x2 - 16) and the second term is a difference of 2 squares, meaning I have: x3 + 5x2 - 16x - 80 = (x + 5)(x + 4)(x - 4)
X3 plus x2 minus 6x plus 4?
x3 + x2 - 6x + 4 = (x - 1)(x2 + 2x - 4)
How do you factor -x5-x3 plus 6x?
-x(x2 - 2)(x2 + 3)
What is the factor of x3-216?
(x - 6)(x2 + 6x + 36)
