x(x-1)
(x - 5)(x + 3)
it is (x-y)(x-y) :)
x2 - 4x - 21 = (x-7)(x+3)
x2 - 6x - 27 = (x-9)(x+3)
It is x^2 -x -12 is (x+3)(x-4) when factored
(x + 2)(x - 9)
(x - 5)(x + 3)
(x + 2)(x - 4)
(x + 1)(x - 8)
x(x - 2)
x(x - 7)
There are no rational factors.
It is not clear what you mean by x^2 minus "factor x". Please add more information and resubmit.
x^(3) - x^(2) - 12x 'x' is a common fractor ' tsker it out. Hence x(x^(2) - x - 12) Factor inside the brackets / x(x - 4(x + 3) Done!!!!!
Without that other number, all you've got is zero.
(x - 2)(2x + 3)
You cannot.