If the polynomial is meant to be x2 + 19 + 10x + 19 then there is no real factorisation. x2 + 19 + 10x + 19 = x2 + 10x + 38 has no real roots and so no real factorisation. Limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible for me to be sure that I have answered the question that you meant to ask. If the polynomial was meant to be something else, please resubmit the question spelling out the symbols as "plus", "minus", "times", "equals", "squared", "cubed" etc. Also, please use "brackets" (or parentheses) because it is impossible to work out whether x plus y squared is x + y2 of (x + y) 2.
If that's + 1, the answer is (10x + 1)(10x + 1) or (10x + 1)2 If that's -1. it gets ugly in a hurry.
-(x + 2)(3x + 4)
(x - 7)(x - 3)
Unfortunately, limitations of the browser used by WA means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc.
3x2 + 10x + 3 = (x + 3)(3x + 1).
x^2 + 10x + 16 = (x + 8)(x + 2)
6x2 + 10x = 2x*(3x + 5)
(x - 7)(x - 3)
(2x - 1)(5x + 8)
They intersect at the point of: (-3/2, 11/4)
X2 + 10X - 13 = 17 add 13 to each side X2 + 10X = 30 halve the linear coefficient ( 10 ), square it and add it to both sides X2 + 10X + 25 = 30 + 25 factor on the left and gather terms on the right (X + 5)2 = 55 (X + 5)2 - 55 = 0 ---------------------------vertex form, (- 5, - 55 ), is the vertex -------------------------------------------[-------------------------------]
(10x-3(10x+3)
20x3 - 70x2 + 60x = 10x(2x2 - 7x + 6) = 10x(2x - 3)(x - 2).
x2 + 9x2 = 10x2
x2 + 10y + 25 doesn't factor neatly. If that was x2 + 10x + 25, it would factor to (x + 5)(x + 5) or (X + 5)2
Using the discriminant of b^2 -4ac = 0 the value of k works out as -2