The factors have imaginary numbers. Let x2 + 2 = 0, so x2 = -2 and x = sqrt(-2) and x = -sqrt(-2)
With i defined as sqrt(-1), we have factorization of (x + i *sqrt(2))*(x - i *sqrt(2))
(a + x^2)(b + y^2)
(x + 3)(x + 2)
2(x + 4)(x + 2)
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
4(x+y)^2
(a + x^2)(b + y^2)
(x + 2)(x + 1)
No
(x+2)(x+2) or (x+2)^2
(x + 3)(x + 2)
2(x + 4)(x + 2)
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
4(x+y)^2
(x + 3)(x - 2)
it is (x-y)(x-y) :)
(x + 5)(x + 2)
2(x^2 + 2)