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Q: How do you find a base of a trapezoid if the height is 9 and the base is 26?

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26 x 3 ie 78 sq units. Formula is base times height, divided by 2.

Base=12m Height=26m Area of Paralellogram=Base x height Area=12 x 26 Area=312m2 Hence the required area of the parallelogram is 312m2

It is: 6.5 cm Check: 0.5*6.5*8 = 26 square cm

The area of a trapezoid is 1/2 times the sum of the bases * the height. In this case, we have the area of 65 = 1/2 * (13+13) * height. Solving for height, we have 65 * 2 / 26, so h = 5. If the two bases of a quadrilateral are of the same length, it is not a parallelogram, but a rectangle.

Length- Height-

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242

trapezoid area = (b1+b2)/2*height trapezoid area = 234 b1=32 b2=20 234 = (32+20)/2*h 234 = 26*h h=9

26 x 3 ie 78 sq units. Formula is base times height, divided by 2.

base: 52 ft

It will be the cube root of 26

Base=12m Height=26m Area of Paralellogram=Base x height Area=12 x 26 Area=312m2 Hence the required area of the parallelogram is 312m2

Area of a triangle = 1/2*base*height. Therefore the area of the triangle = 1/2*4*13 = 26 square feet.

The area of a trapezoidal pool with a height of 15 yards and bases of 14 and 26 yards is 0.5*(14+26)*15 = 300 square yards. The area of a trapezoid is 1/2 of the sum of the bases times the height.

The hypotenuse of a right triangle with a base of 24 inches and height of 10 inches is: 26 inches.

26 feet

It is: 6.5 cm Check: 0.5*6.5*8 = 26 square cm

The area of a trapezoid is 1/2 times the sum of the bases * the height. In this case, we have the area of 65 = 1/2 * (13+13) * height. Solving for height, we have 65 * 2 / 26, so h = 5. If the two bases of a quadrilateral are of the same length, it is not a parallelogram, but a rectangle.

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