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By raising e (≈ 2.7182818...) to the number:
If m = loge n, then n = em
This calculation I would do either with log tables, a scientific calculator, a slide rule, or by working out enough terms of the series using a basic calculator (with a memory) or a pencil and paper:
em = 1 + Σ1/r! mr
for r=1 to as many terms as needed to get the required accuracy wanted.
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How do you find antilog of any number i?
Find the base for the logarithm: it is likely to be 10 if you are a newcomer to logs or e (= 2.71828...) if you are more advanced. Then the antilog of x is 10x or ex.
How to find antilog negative number?
If it is log to the base 10, use the calculator to find 10 to that power. If it is log to the base e, use the calculator to find e to that power. Both the above are standard functions on all scientific calculators and are easy to work out on spreadsheets. Alternatively, you can find the antilog of the absolute value and then find the reciprocal. Thus antilog(-3.5) = 1/antilog(3.5) etc.
How do you find anti log of a number?
First you must decide what basis you are using for logarithms. Often this will be the number 10, or the number e. (In theory, any number greater than 1 will work.) Then you just raise the base to your number. For example, the antilog (base-10) of 5 is simply 105 = 100,000. Your scientific calculator should have an antilog key.
How do you use the calculator to find the cube root?
Depends on your calculator. If you have "raise to the power" then use "raise to the power 1/3". If not, try logs: either logs to base 10 or logs to base e will do: find the log, divide it by 3, then find the antilog. For base e, (log sometimes written "ln" meaning "natural log") the antilog is just the exponential : " ex ".
How can you solve root 35?
sqrt(35) = ± 5.9161 It is usually simple with a scientific calculator or computer but not so otherwise. If you have access to log and antilog tables, you can look up log(35) which is 1.5441 Multiply that by 0.5 (square root is the same as power 0.5) to give 0.7720 And then look up the antilog of that to give 5.9161. [Antilog 0.7720 = 100.7720] You could take logs to any base: 10, e or another number, but 10 and e are the most widely used. Finally, there is a method that resembles long division but it is too complicated for me to explain here.
