The inverse cos of 1 is equal to o degrees. You can find this answer by knowing what angle measurement has cos equal to a value of 1.
Its a ratio in a right angle triangle, cos angle = adjacent / hypotonuse.
Use the cosine rule. If a, b and c are the sides with angle A opposite side a, then 2bc*cos(A) = b2 + c2 - a2 so that Angle A = cos-1[(b2 + c2 - a2)/(2bc)]
a = 3/sqrt(2)*i + 3/sqrt(2)*jb = 5ja.b = |a|*|b|*cos(q)= 3*5*cos(45) = 15/sqrt(2)
To find the hypotenuse with angle a and side b, we use the identity below:cos(a) = b/cWe have a and b, and to find c, we multiply both sides by c and divide both sides by cos(a):c = b/cos(a)c = 5/cos(30)c = 32.41460617mm
The cosine function is an even function which means that cos(-x) = cos(x). So, if cos of an angle is positive, then the cos of the negative of that angle is positive and if cos of an angle is negative, then the cos of the negative of that angle is negaitive.
A Quadrantal angle is an angle that is not in Quadrant I. Consider angle 120. You want to find cos(120) . 120 lies in quadrant II. Also, 120=180-60. So, it is enough to find cos(60) and put the proper sign. cos(60)=1/2. Cosine is negative in quadrant II, Therefore, cos(120) = -1/2.
A Quadrantal angle is an angle that is not in Quadrant I. Consider angle 120. You want to find cos(120) . 120 lies in quadrant II. Also, 120=180-60. So, it is enough to find cos(60) and put the proper sign. cos(60)=1/2. Cosine is negative in quadrant II, Therefore, cos(120) = -1/2.
The inverse cos of 1 is equal to o degrees. You can find this answer by knowing what angle measurement has cos equal to a value of 1.
sin, tan and cos can be defined as functions of an angle. But they are not functions of a triangle - whether it is a right angled triangle or not.
You need to use trigonometry cosine (angle) = length/diagonal diagonal = length/cos(angle)
What is the angle with a cosine of 0.6946
Its a ratio in a right angle triangle, cos angle = adjacent / hypotonuse.
Power factor = cos (angle)PF=cos @
Use trigonometry and the cosine ratio: cos = adj/hyp and when rearraged hyp = adj/cos
cos(30)cos(55)+sin(30)sin(55)=cos(30-55) = cos(-25)=cos(25) Note: cos(a)=cos(-a) for any angle 'a'. cos(a)cos(b)+sin(a)sin(b)=cos(a-b) for any 'a' and 'b'.
Use the cosine rule. If a, b and c are the sides with angle A opposite side a, then 2bc*cos(A) = b2 + c2 - a2 so that Angle A = cos-1[(b2 + c2 - a2)/(2bc)]