depends on the branch of math, and the math function/relation you are talking about
perimeter of what quadrant?
Yes, if it is the closed interval. No, if it is the open interval.
The lower boundary of the median class in a frequency distribution is the smallest value that defines the class interval containing the median. To find it, you first determine the cumulative frequency and identify the class interval where the median lies, which is typically the class with a cumulative frequency that exceeds half of the total frequency. The lower boundary is then the starting point of that specific class interval.
You find the the smallest and largest values. The interval is the largest minus the smallest.
In the first quadrant.
perimeter of what quadrant?
An equality defines a specific point (or points). An inequality can define an interval.
Pi / 5 would be in Quadrant I.
U find the word interval
It is not possible. A quadrant extends infinitely far in two directions and so has no centre.
If you the radius of the circle is r then the perimeter of a quadrant = r*(2 + pi/2).
Yes, if it is the closed interval. No, if it is the open interval.
If the radius of the circle is r, then the area of the quadrant is 0.25*pi*r^2
If A is in quadrant IV, then A/2 is in quadrant II. Yes, the fact than cos(A) is 0.1 means that A is in quadrant I or IV, but it really is not required in order to answer the question. It is superfluous.
what is the lunitidal interval of pireaus;
You find the the smallest and largest values. The interval is the largest minus the smallest.
In the first quadrant.