Q: Factor ac plus ad plus bc plus bd?

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(a + b)(b + c)

A+BC+AC+B=A+BC+AC+B unless any of these variables has an assigned value.

never A+ :))

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No, four lines can can have 6 total intersections. They would be Ab, Ac, Ad, Bc, Bd, and Cd

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(a + b)(b + c)

(a + b)/(a - b) = (c + d)/(c - d) cross multiply(a + b)(c - d) = (a - b)(c + d)ac - ad + bc - bd = ac + ad - bc - bd-ad + bc = -bc + ad-ad - ad = - bc - bc-2ad = -2bcad = bc that is the product of the means equals the product of the extremesa/b = b/c

yes because ab plus bc is ac

Take the BC year and add it to the AD year with present year and bc & ad

6(b - ac + b2 - bc)

6(ab - ac + b2 - bc)

A+BC+AC+B=A+BC+AC+B unless any of these variables has an assigned value.

It is possible, depending on what on earth AC and BC are!

associative? single replacement

Yes, for example (a + bi)(c + di) = ac + adi + bic + bidi, and commutative property works as well --> ac + adi + bci + bdiÂ² --> ac + (ad + bc)i + bd(-1) = (ac - bd) + (ad + bc)i

15 ac + 20 bc + 6 ad + 8 bd =3a (5c + 2d) + 4b (5c + 2d) =(3a + 4b) (5c + 2d)

never A+ :))