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What else can I help you with?
How do you factor ab plus bc plus b2 plus ac?
(a + b)(b + c)
What type of reaction is the generic equation A plus BC AC plus B?
A+BC+AC+B=A+BC+AC+B unless any of these variables has an assigned value.
AC plus BC could equal 15?
never A+ :))
Can you factor this ab plus 3a-bc-3c?
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Can four lines have only two intersection points?
No, four lines can can have 6 total intersections. They would be Ab, Ac, Ad, Bc, Bd, and Cd
How do you factor ab plus bc plus b2 plus ac?
(a + b)(b + c)
How is a plus b over a minus b equals c plus d over c minus d?
(a + b)/(a - b) = (c + d)/(c - d) cross multiply(a + b)(c - d) = (a - b)(c + d)ac - ad + bc - bd = ac + ad - bc - bd-ad + bc = -bc + ad-ad - ad = - bc - bc-2ad = -2bcad = bc that is the product of the means equals the product of the extremesa/b = b/c
Can AC plus AD plus BC plus BD can be factored as (A plus C)(B plus D)?
Yes, the expression AC + AD + BC + BD can be factored as (A + C)(B + D). This is evident by applying the distributive property, where expanding (A + C)(B + D) yields AB + AD + BC + CD. The terms AC and BD are not present, so the expression can be expressed in a different form, but the original expression itself represents a different factoring structure.
If ab plus bc equals ac then ac equals ab plus bc?
yes because ab plus bc is ac
How do you solve this a squared minus b squared plus ac minus bc?
a^(2) - b^(2) + ac - bc Factor ( a - b)( a + b) + c(a - b) Factor further (a - b)(a + b + c) Done!!!!!
How to calculate years using bc from ac?
Take the BC year and add it to the AD year with present year and bc & ad
Factor 6b minus 6ac plus 6b squared minus 6bc?
6(b - ac + b2 - bc)
Factor 6ab minus 6ac plus 6b squared minus 6bc?
6(ab - ac + b2 - bc)
What type of reaction is the generic equation A plus BC AC plus B?
A+BC+AC+B=A+BC+AC+B unless any of these variables has an assigned value.
What kind of reaction is A plus BC æ B plus AC?
associative? single replacement
Is AC plus BC could equal 15?
It is possible, depending on what on earth AC and BC are!
Does distributive property apply to complex numbers?
Yes, for example (a + bi)(c + di) = ac + adi + bic + bidi, and commutative property works as well --> ac + adi + bci + bdi² --> ac + (ad + bc)i + bd(-1) = (ac - bd) + (ad + bc)i
