The original equation f(x) = 6/(x+3) can be rewritten as f(x) = 6(x+3)-1. Now derive the equation according the the power rule and the chain rule:
y = 6 (x+3)-1
dy/dx = 6 (-1)(x+3)-2(1)*
dy/dx = -6/(x+3)2
* by the chain rule, you must multiply by the derivative of which is simply one.
Thus, the derivative of f(x) = 6/(x+3) equals -6/(x+3)2
y is a sum of constants and so is itself a constant. Its derivative is, therefore, zero.
14x
There are several steps involved in how one can solve the derivative x plus y - 1 equals x2 plus y2. The final answer to this math problem is y'(x) = (1-2 x)/(2 y-1).
if y=aex+be2x+ce3x then its derivative dy/dx or y' is: y'=aex+2be2x+3ce3x
Rprime= 2q + 2a + 3 Rdoubleprime= 4
y is a sum of constants and so is itself a constant. Its derivative is, therefore, zero.
x = 10x, so derivative = 10
14x
The first derivative is m and the second is 0 so the third is also 0.
Following the correct order of operations: derivative of x^2 + 6/2 = derivative of x^2 +3, which equals 2x
There are several steps involved in how one can solve the derivative x plus y - 1 equals x2 plus y2. The final answer to this math problem is y'(x) = (1-2 x)/(2 y-1).
if y=aex+be2x+ce3x then its derivative dy/dx or y' is: y'=aex+2be2x+3ce3x
y"+y'=0 is a differential equation and mean the first derivative plus the second derivative =0.Look at e-x the first derivative is -e-xThe second derivative will be e-xThe sum will be 0
Rprime= 2q + 2a + 3 Rdoubleprime= 4
The answer to 1 over 2x plus 13 equals 9 is x equals -8.
It is 2.
y = x2 + 12x + 21At the max or min point, the first derivative of the function = 0.2x + 12 = 02x = -12x = -6