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There are often multiple 'correct' dimensions for these problems. The most straight forward way to solve it is to list all the factors that, when multiplied, equal the area. Then from this list, cross out the factors that DON'T equal your perimeter. The remaining factors are your possible dimensions.
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How to find the perimeter and area of a rectangle?
To find the perimeter you add and to find the area we multiply.
A rectangle has a perimeter of 72m If the length is 20 m longer than the width find its dimensions?
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
What does a rectangle with an area of 24 and a perimeter of 22?
To find the dimensions of a rectangle with an area of 24 and a perimeter of 22, we can use the formulas for area (A = length × width) and perimeter (P = 2(length + width)). Let the length be ( l ) and the width be ( w ). From the area, we have ( lw = 24 ), and from the perimeter, ( 2(l + w) = 22 ), simplifying to ( l + w = 11 ). Solving these equations simultaneously, we find the dimensions are ( l = 8 ) and ( w = 3 ) (or vice versa).
How do you find the dimensions of the area of a rectangle?
The dimensions for area are [L2]
How do you find the perimeterof a rectangle in square feet?
If the dimensions of the rectangle are in feet, the perimeter will be in feet as well. The area will be in square feet. The area is length x width. The perimeter is 2 x (length + width) or 2 x length + 2 x width.
How can you find the answer for the perimeter and area of a rectangle?
find the perimeter and area of a rectangle that is 15cm long and 5cm wide
How do you find the dimensions of a rectangle given only the total perimeter?
Length + width = half the perimeter, but more info eg area, is needed.
Find the dimensions of the rectangle with an area of 100 square units and whole-number side lengths that has the largest perimeter or the smallest perimeter?
Type your answer here... give the dimensions of the rectangle with an are of 100 square units and whole number side lengths that has the largest perimeter and the smallest perimeter
The length of a rectangle is twice its width If the perimeter of the rectangle is 54y find its area?
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
What is the perimeter of a rectangle that has an area of 432 feet?
Ah, what a lovely question! To find the perimeter of a rectangle, we need to know both the length and width. Since the area is 432 square feet, we can find the dimensions by factoring 432 into pairs of numbers until we find a pair that could be the length and width of the rectangle. Once we have the dimensions, we can simply add up all the sides to find the perimeter.
How to find the perimeter and area of a rectangle?
To find the perimeter you add and to find the area we multiply.
The length of a rectangle is 5 more then the width Find the perimeter and the area of the rectangle?
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
A rectangle has a perimeter of 72m If the length is 20 m longer than the width find its dimensions?
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
A rectangle that is 12 cm in area and 16 in perimeter?
To find the dimensions of the rectangle, we need to set up equations based on the given area and perimeter. The area of a rectangle is length multiplied by width, so length times width equals 12 cm. The perimeter of a rectangle is given by the formula 2(length + width), which in this case equals 16 cm. By solving these two equations simultaneously, we can find the dimensions of the rectangle.
How do you find the area of a rectangle with a perimeter of 36m?
how do you find the area of a rectangle witha perimeter of 36 in You don't. You need more information For example a 1 x 17 rectangle has a perimeter of 36 and its area is 17. But a 2 x 16 rectangle also has a perimeter of 36 and its area is 32.
What does a rectangle with an area of 24 and a perimeter of 22?
To find the dimensions of a rectangle with an area of 24 and a perimeter of 22, we can use the formulas for area (A = length × width) and perimeter (P = 2(length + width)). Let the length be ( l ) and the width be ( w ). From the area, we have ( lw = 24 ), and from the perimeter, ( 2(l + w) = 22 ), simplifying to ( l + w = 11 ). Solving these equations simultaneously, we find the dimensions are ( l = 8 ) and ( w = 3 ) (or vice versa).
How do you find the dimensions of the area of a rectangle?
The dimensions for area are [L2]
