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Gradient = [7 - (-9)]/[3 - (-1)] = 16/4 = 4

So the equation is (y - 7) = 4*(x - 3)

or y - 7 = 4x - 12

The standard form, therefore, is 4x - y - 5 = 0

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Q: How do you find the equation of the line that passes 3 7 and -1 -9?
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