Gradient = [7 - (-9)]/[3 - (-1)] = 16/4 = 4
So the equation is (y - 7) = 4*(x - 3)
or y - 7 = 4x - 12
The standard form, therefore, is 4x - y - 5 = 0
y=7/3x-13
(2, 1) and (5, 5) find slope m = Y2 - Y1/X2 - X1 m = 5 -1/5 - 2 m = 4/3 ===============equation of the line
It is a straight line equation in the form of: y = x
Y=2x-1
It is y = 2.
y=7/3x-13
which equation has a slope of -1/2 and a graph that passes through (-3,4)?
If you mean (1, 2) and (3, 4) then its equation is y = x+1
0
(2, 1) and (5, 5) find slope m = Y2 - Y1/X2 - X1 m = 5 -1/5 - 2 m = 4/3 ===============equation of the line
It is a straight line equation in the form of: y = x
y = 6x + 1
Slope-intercept form
It is: y = -2x-2
It is y = 2.
Y= -3x + 8
Y=2x-1