27836/56 gives 497 and 4 as quotient and remainder
Dividend- remainder =27836-4 = 27832 which is divisible by 56. So the least no that to be subracted is 4
To find the number that should be subtracted from 63700 to make it exactly divisible by 18, first, calculate the remainder when 63700 is divided by 18. Dividing 63700 by 18 gives a quotient of 3538 and a remainder of 16. Therefore, to make 63700 divisible by 18, you need to subtract this remainder (16) from 63700. Thus, subtracting 16 will yield 63684, which is divisible by 18.
To find the least number to be subtracted from 86295031 so that the remainder is divisible by 582, we first determine the remainder of 86295031 when divided by 582. Calculating (86295031 \mod 582) gives a remainder of 505. Therefore, to make the number exactly divisible by 582, we need to subtract this remainder, resulting in (505). Thus, the least number to subtract is 505.
To make a number divisible by 10, its last digit must be 0. The last digit of 23483 is 3. Therefore, to make it divisible by 10, you should subtract 3 from 23483. This means the least number that should be subtracted is 3.
It would help if you could insert the relevant numbers in the copy/paste!
832/48 gives 17 as quotient and 16 as remainder. Dividend-remainder=divisor*quotient 832-16 = 48*17 which is 816 that is divisible by 48. So 16 to be subracted.
To find the number that should be subtracted from 63700 to make it exactly divisible by 18, first, calculate the remainder when 63700 is divided by 18. Dividing 63700 by 18 gives a quotient of 3538 and a remainder of 16. Therefore, to make 63700 divisible by 18, you need to subtract this remainder (16) from 63700. Thus, subtracting 16 will yield 63684, which is divisible by 18.
It is: 16 because 18448-16 = 18432 and 18432/48 = 384
To find the least number to be subtracted from 86295031 so that the remainder is divisible by 582, we first determine the remainder of 86295031 when divided by 582. Calculating (86295031 \mod 582) gives a remainder of 505. Therefore, to make the number exactly divisible by 582, we need to subtract this remainder, resulting in (505). Thus, the least number to subtract is 505.
To make a number divisible by 10, its last digit must be 0. The last digit of 23483 is 3. Therefore, to make it divisible by 10, you should subtract 3 from 23483. This means the least number that should be subtracted is 3.
which least number should be subtracted from 1000 so that 30 divides the difference exactly
The answer is 48illustration:833 is a multiple of 49 which is more than 832the multiple which is immediately less than 833 is 784so the difference that must be subtracted is 832- 784 = 48
32575/9 gives 3619 as quotient 4 as remainder. now from 32575 subtract the remainder 4 that is 32571. this is divisible by 9. 4 should be
It would help if you could insert the relevant numbers in the copy/paste!
832/48 gives 17 as quotient and 16 as remainder. Dividend-remainder=divisor*quotient 832-16 = 48*17 which is 816 that is divisible by 48. So 16 to be subracted.
To find the least number that should be added to 924 to make it exactly divisible by 48, we need to find the remainder when 924 is divided by 48. The remainder is 12. Therefore, the least number that should be added to 924 to make it exactly divisible by 48 is 48 - 12, which equals 36.
2,789/10= 2,78.9. Just move the decimal place over one spot. So, if the answer has to be a whole number, not a fraction, then please subtract 9 from the number to get 2,780. No fraction.
Dividend-remainder=divisor *quotient 9660/76 gives 127 quotient and 8 remainder 9660-8=76*127 9652 so 8 must be subracted from 9660 ans is 8