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What is the least number that should be subtracted from 27836 so that it is exactly divisible by 56?
27836/56 gives 497 and 4 as quotient and remainder
Dividend- remainder =27836-4 = 27832 which is divisible by 56. So the least no that to be subracted is 4
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What least number should be subtracted from 86295031 so that the remainder is exactly divisible by 582?
To find the least number to be subtracted from 86295031 so that the remainder is divisible by 582, we first determine the remainder of 86295031 when divided by 582. Calculating (86295031 \mod 582) gives a remainder of 505. Therefore, to make the number exactly divisible by 582, we need to subtract this remainder, resulting in (505). Thus, the least number to subtract is 505.
What least number should be subtracted from 23483 to make it divisible by 10?
To make a number divisible by 10, its last digit must be 0. The last digit of 23483 is 3. Therefore, to make it divisible by 10, you should subtract 3 from 23483. This means the least number that should be subtracted is 3.
What least number should be subtracted from it to make it divisible by?
It would help if you could insert the relevant numbers in the copy/paste!
What is the least number that should be subtracted from 832 to make it exactly divisible by 48?
832/48 gives 17 as quotient and 16 as remainder. Dividend-remainder=divisor*quotient 832-16 = 48*17 which is 816 that is divisible by 48. So 16 to be subracted.
What is the least number that should be added to 924 to make it exactly divisible by 48?
To find the least number that should be added to 924 to make it exactly divisible by 48, we need to find the remainder when 924 is divided by 48. The remainder is 12. Therefore, the least number that should be added to 924 to make it exactly divisible by 48 is 48 - 12, which equals 36.
