To find the product of two integers, you multiply them together using the multiplication operation. For example, if you have integers ( a ) and ( b ), their product is calculated as ( a \times b ). You can perform this multiplication using various methods, such as repeated addition, the standard algorithm, or using a calculator. The result will be a single integer representing the total value of the multiplication.
Multiply them.
Let the two consecutive negative odd integers be ( x ) and ( x + 2 ). The equation for their product is ( x(x + 2) = 399 ). This simplifies to ( x^2 + 2x - 399 = 0 ). Solving this quadratic equation, we find that the integers are ( -19 ) and ( -17 ), since ( -19 \times -17 = 399 ).
2, -3, 6.
A counterexample to the conjecture that the sum of any two integers greater than 1 is less than their product is the pair (2, 2). The sum of these integers is 2 + 2 = 4, while their product is 2 × 2 = 4. Here, the sum equals the product, demonstrating that the conjecture does not hold for all integers greater than 1.
11 & 14
1. find the product of the first two 2. multiply that product with the third number
-46
Yes, the product of 2 integers are always an integers. ex. -2*3=-6
The product of the two integers is -80.
Multiply them.
9240 is the product of the three consecutive integers 20, 21, and 22.
The product of 2 consecutive positive number is 48. Find the 2 numbers
Yes, the integers are 12 and 13.
That's any two positive integers and one negative integer. Ex.: 1 x -1 x 2 = -2
2 and 91
Let the two consecutive negative odd integers be ( x ) and ( x + 2 ). The equation for their product is ( x(x + 2) = 399 ). This simplifies to ( x^2 + 2x - 399 = 0 ). Solving this quadratic equation, we find that the integers are ( -19 ) and ( -17 ), since ( -19 \times -17 = 399 ).
2, -3, 6.