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What else can I help you with?
How do you find a product of a integers?
Multiply them.
Find two consecutive negative odd integers whose product is 399?
Let the two consecutive negative odd integers be ( x ) and ( x + 2 ). The equation for their product is ( x(x + 2) = 399 ). This simplifies to ( x^2 + 2x - 399 = 0 ). Solving this quadratic equation, we find that the integers are ( -19 ) and ( -17 ), since ( -19 \times -17 = 399 ).
Find 3 integers whose product is negative 36 and whose sum is 5?
2, -3, 6.
The sum of 2 integers is 25 Their product is 154 Name the integers?
11 & 14
Two consecutive positive integers have a product of 156 find the smaller integer?
13 and 12 are the two integers that have the product of 156 and 12 is the smaller of the two.
How do you find the product of three negative integers?
1. find the product of the first two 2. multiply that product with the third number
Find two integers that have a product of -48 and a sum of -2?
-46
Is the product of any two integers an integer?
Yes, the product of 2 integers are always an integers. ex. -2*3=-6
Two integers have a difference of -18 and a sum of 2 What is the product of the two integers?
The product of the two integers is -80.
How do you find a product of a integers?
Multiply them.
The product of three consecutive integers is 9240 find the integers?
9240 is the product of the three consecutive integers 20, 21, and 22.
The product of 2 positive consecutive even integers is 48 What is the smaller number?
The product of 2 consecutive positive number is 48. Find the 2 numbers
The product of two consecutive integers is 156?
Yes, the integers are 12 and 13.
What are 2 integers have a product of 182?
2 and 91
Find 3 integers whose product is neg?
That's any two positive integers and one negative integer. Ex.: 1 x -1 x 2 = -2
Find two consecutive negative odd integers whose product is 399?
Let the two consecutive negative odd integers be ( x ) and ( x + 2 ). The equation for their product is ( x(x + 2) = 399 ). This simplifies to ( x^2 + 2x - 399 = 0 ). Solving this quadratic equation, we find that the integers are ( -19 ) and ( -17 ), since ( -19 \times -17 = 399 ).
Find 3 integers whose product is negative 36 and whose sum is 5?
2, -3, 6.
