Find a common denominator by finding the LCM of the dissimilar denominators and converting the fractions to equivalent fractions with the same denominator. Then add the numerators and put that sum over the common denominator. Reduce if possible. Example: 1/5 + 1/6 The least common denominator of 5 and 6 is 30. 1/5 = 6/30 1/6 = 5/30 1/5 + 1/6 = 11/30
29 and 30.
1 + 2 + 3 + 5 + 6 + 10 + 15 + 30 = 62.
1+1+1
Let the numbers be 3x and x:- 3x+x = 30 4x = 30 Diivide both sides by 4 x = 7.5 So the numbers are 22.5 and 7.5
The two numbers are 5 and -6. 5x(-6) = -30 so the product is -30 and 5+(-6) = -1 so the sum is -1
The sum of whole numbers 1 through 30 is 465.
(30 + 1) * 30/2 ie 465
The product of a sum and a difference with 31 times 29 is:(30+1) x (30-1)sum to differencemakea product= 30² - 1²= 900 - 1= 899
Find a common denominator by finding the LCM of the dissimilar denominators and converting the fractions to equivalent fractions with the same denominator. Then add the numerators and put that sum over the common denominator. Reduce if possible. Example: 1/5 + 1/6 The least common denominator of 5 and 6 is 30. 1/5 = 6/30 1/6 = 5/30 1/5 + 1/6 = 11/30
10 for t = 1 to 50 20 input a 30 c = c + a 40 next t 50 print c
You find the sum of two numbers by adding the two together. Example: The sum of 1 + 1 is 2
Highway Thru Hell - 2012 After the Crash 1-9 was released on: Canada: 30 October 2012 USA: 30 October 2012
To calculate the sum of the numbers 1 to n, the formula is: sum = n(1 + n) / 2 So, an equation to find the sum of the integers 1 to 2010 is: sum = 2010 x (1 + 2010) / 2
465
The total is 465
The arithmetic sequence of odd integers is 1, 3, 5, 7, 9, ... where the common difference is 2. The sum of the first thirty odd integers can be found by using the sum formula such as: Sn = n/2[2a1 + (n - 1)d], where a1 = 1, n = 30, and d = 2. So, S30 = (30/2)[(2)(1) + (30 - 1)(2)] = (15)[2 + (29)(2)] = (15)(60) = 900