Exactly the same as for a non-floating object. Finding the volume of a shape does not vary, (i.e it's always something along the lines of height*width*depth, or area of base *height. "Table" or "surface" is irrelevant, since if it not a variable in the formula). This is true whether the object is floating or not.
The volume of liquid displaced has the same mass as the floating object.
To find the volume of an object, we use an overflow cylinder as it gives a measure of the volume of the object by displacing an equal amount of water into the beaker.
The answer depends on what information you do have about the object.
The volume of a rectangle is 0. It is a 2-dimensional object and so has no volume.
The measure, in cubic centimetres IS the volume!
To calculate the density of an irregular shaped floating object, you can measure its mass using a balance and then find its volume by submerging it in a known volume of water and measuring the water displaced. For a regular shaped floating object, you can simply divide its mass by its volume to find the density.
The volume of liquid displaced has the same mass as the floating object.
652 cc (unless it was floating).
To predict the density of a floating object, you can compare the density of the object to the density of the fluid it is floating in. For an object to float, its density must be less than the density of the fluid. You can calculate the density of the object by dividing its mass by its volume.
It's true that the volume of displaced water of a floating object equalst the portion of that object that is underwater.
A floating object is an object that is floating, which is a floating object. Which = floating object.
If you can determine the volume fractions of the object that are above and below the water, then you can find the density of the object by multiplying the density of the fluid it floats in by the fraction of the volume that is below the surface of the liquid. Another, more complex way is to weigh the object alone then attach it to one arm of a balance to weigh the object when it is floating. As it floats it will displace an amount of liquid equal in weight to the total object. The decrease in weight will be proportional to the fraction of the object that is submerged. As an example: If an object weighed 100 grams out in the air but only required 20 grams to counterbalance its weight when it is floating, and the fluid it was floating in was water, then the density of the object would be (1 g/cubic centimeter)·(100-20)/100 = 0.8 g/cubic centimeter.
Yes. The floating object is an addition to the mass system, even though it cannot displace its entire volume in the water.
True. According to Archimedes' principle, the volume of water displaced by an object floating in a fluid (like water) is equal to the volume of the part of the object that is submerged in the fluid.
The volume of the water displaced by an object floating in a liquid is equal to the volume of the portion of the object that is submerged in the liquid. This is known as Archimedes' principle, which states that the buoyant force on an object is equal to the weight of the fluid displaced by the object.
Look at the LAST WORD of the question, they switch it sometimes if it is: Underwater than it is TRUE, If it's Surface of the water than it is FALSE ~
False - Apex