Q: How do you find the width of a right triangle?

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You cannot since there is not enough information.

The area of a right angled triangle would be .5 * length *width where the length is the height of the triangle. To find the height of the triangle, take the sine of 45 degrees, which is the degree of the angles other than the 90 degrees, and multiply it by the length of one of the two equal sides. The width of the triangle is the length of the bottom side.

if the triangle has one right angle in it

Assuming a right-angle triangle whose length is vertical, and the width is the base, then (14×8) ÷ 2 = 56 square units.

Lenght X Width, then you divide the number by 2.

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You cannot since there is not enough information.

The answer will depend on whether the length is the hypotenuse or one of the legs of the triangle.

width x highest point on the triange then divide by 2 if equilateral/isoceles triange height x width then divide by 2 if right angled triange/scalene triangle

The area of a right angled triangle would be .5 * length *width where the length is the height of the triangle. To find the height of the triangle, take the sine of 45 degrees, which is the degree of the angles other than the 90 degrees, and multiply it by the length of one of the two equal sides. The width of the triangle is the length of the bottom side.

It depends on the information that you have.

It depends on what information you have.

Measure it!

Using Pythagoras' theorem for a right angle triangle it is 11.662 cm rounded to 3 d.p.

if the triangle has one right angle in it

It depends on the information available to you.

Any one of the lengths can be taken as the width.

Assuming a right-angle triangle whose length is vertical, and the width is the base, then (14×8) ÷ 2 = 56 square units.