The easiest way is to graph it, but if they want it done with algebra, it's a multi-step process. Let's say the points are (2, 3) and (4, 5)
Step one: get the slope
Slope = (y2 - y1) / (x2 -x1) where y1 is the y-coordinate on the first point, and y2 is the y-coordinate on the second point. The same is true for x1 and x2.
Slope = (5 - 3) / (4 - 2) = 1
Step two: plug the slope into the equation for a line: y = mx + b where m is the slope, x is the x-intercept, and b is the y-intercept.
y = (1)x + b
Step three: get the y-intercept (b): to get this, you need to plug in one of the points (it doesn't matter which one) for y and x. Let's take point (2, 3).
3 = (1)(2) + b - notice I replaced y with 3 and x with 2.
Now, solve for b.
3 = 2 + b
b = 1
Step four: Get the x-intercept. The x-intercept is always where y = 0 (0,0), so we plug 0 in for y on the equation using the information we've acquired and solve for x.
0 = (1)x + 1
0 = 1x + 1, or 0 = x + 1
x = -1
Therefore, the x-intercept is -1 and the y-intercept is 1.
If it's a straight line, then that's all you need. Find the 'x' and 'y' intercepts,lay your ruler down between the two points, and draw your line.
Your x and y intercepts give you two points on the line of the graph. Use these two points in the slope equation m = (y2-y1)/(x2-x1), and that gives you the slope.
Slope: -1 intercepts: (0,1000),(1000,0)
Bisect two arcs above and below the given points or line and the perpendicular of these arcs cuts through the midpoint.
That depends on the points in order to find the slope whereas no points have been given.
Draw the axes. Plot the two intercepts. Draw a line connecting the two points
If it's a straight line, then that's all you need. Find the 'x' and 'y' intercepts,lay your ruler down between the two points, and draw your line.
Your x and y intercepts give you two points on the line of the graph. Use these two points in the slope equation m = (y2-y1)/(x2-x1), and that gives you the slope.
Parallel straight line equations have the same slope but with different y intercepts
Slope: -1 intercepts: (0,1000),(1000,0)
There is no limit to the number of y-intercepts a line can have. The axis itself is a line and it intercepts itself an infinite number of times.
As Anand said, the question is vague. However, two important points for any equation are the x and y intercepts. For y = 2x, the x-intercept is (0,0) and the y-intercept is (0,0). Not sure if that helps.
Bisect two arcs above and below the given points or line and the perpendicular of these arcs cuts through the midpoint.
The equation is -x -16 equals y. You find this by using the equation for a line mx plus b equals y, where 'm' is the slope and 'b' is the y-intercept. From the information given, you have two points which are 0.-16 ans -16,0. You can find 'm' the slope with the equation y2-y1/x2-x1, or -16-0/0- -16. This is -16/16 or -1 for m and the y-intercept is given as -16. So, substitute into the line equation these values to get the answer given.
Gradients can be worked out by: 1. gradient formula, suppose the two points are (x1,y1); (x2,y2) then the gradient=(y2-y1)/(x2-x1) 2. rise/run Intercepts can be found by: 1. to find the x-intercept substitute y=0 into the equation of the line 2. to find the y-intercept substitute x=0 into the equation of the line
If the lines have the same slope but with different y intercepts then they are parallel
That depends on the points in order to find the slope whereas no points have been given.