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How do you find the y-coordinate vertex of a parabola?
Once you calculate the X coordinate using the axis of symmetry (X=-b/2a), you plug that value in for all of the X's in the equation of the parabola. You then solve the equation for the value of Y.
How do you find the vertex of an equation in standard form?
To find the vertex of a quadratic equation in standard form, (y = ax^2 + bx + c), you can use the vertex formula. The x-coordinate of the vertex is given by (x = -\frac{b}{2a}). Once you have the x-coordinate, substitute it back into the equation to find the corresponding y-coordinate. The vertex is then the point ((-\frac{b}{2a}, f(-\frac{b}{2a}))).
How do you find equation when 2 equations and 1 coordinate is given?
By solving the simultaneous equations the values of x and y should be equal to the given coordinate
Which value represents the x-coordinate of the vertex in the equation y xsquared 6x - 2?
To find the x-coordinate of the vertex in the quadratic equation ( y = x^2 + 6x - 2 ), you can use the formula ( x = -\frac{b}{2a} ), where ( a = 1 ) and ( b = 6 ). Plugging in the values, ( x = -\frac{6}{2 \times 1} = -3 ). Therefore, the x-coordinate of the vertex is ( -3 ).
The of a graph is the point where the y-coordinate is 0.?
The x-intercept of a graph is the point where the y-coordinate is 0. It represents the value of x at which the graph intersects the x-axis. To find the x-intercept, you can set the equation of the graph equal to zero and solve for x.
How do you find the y-coordinate vertex of a parabola?
Once you calculate the X coordinate using the axis of symmetry (X=-b/2a), you plug that value in for all of the X's in the equation of the parabola. You then solve the equation for the value of Y.
How can you determine if an ordered pair is a solution to an equation?
plug the x coordinate in the x part of the equation and plug the y coordinate in the y's part of the equation and solve
How do you find the vertex of an equation in standard form?
To find the vertex of a quadratic equation in standard form, (y = ax^2 + bx + c), you can use the vertex formula. The x-coordinate of the vertex is given by (x = -\frac{b}{2a}). Once you have the x-coordinate, substitute it back into the equation to find the corresponding y-coordinate. The vertex is then the point ((-\frac{b}{2a}, f(-\frac{b}{2a}))).
How do you find equation when 2 equations and 1 coordinate is given?
By solving the simultaneous equations the values of x and y should be equal to the given coordinate
How do you find the vertex of the parabola associated with a quadratic equation?
You must first solve the equation for x, find the midpoint between the two x coordinates and substitute it into the equation to find the y coordinate I.E. If your equation was y=x^2+4x-5 1. Factorise the Equation and solve for x. x^2+4x-5 = (x+5)(x-1) So x+5=0 x = 0 - 5 x=-5 And x-1=0 x = 0 + 1 x = 1 So x = -5,1 Find the mid point/average: (-5+1)/2 = -2 So the x coordinate of the vertex is -2. Substitute this into the equation x^2+4x-5: (-2)^2 + 4*(-2) - 5 = 4 - 8 - 5 = -9 So the Coordinate of the vertex is (-2,-9). Hope this Helps, message me if you want more info.
How do you get the answer for a linear equation if the equation is in y equals mx plus b?
Well, you take y=mx+b and you fill in the numbers M= slope y= y-coordinate x= x-coordinate
A vertical line in an x-y coordinate system?
A vertical line in the xy coordinate plane would represent the line of an equation such as x = 1 or x = -4.
What is the y coordinate of 6 in the linear equation x equals 7-y?
Assuming 6 refers to the value of x, the y coordinate is 1
How do you write an equation for the coordinate (3,1)?
The equation of coordinate is 3x+y=0.
How do you write an equation in standard form of a circle?
(x - h)2 + (y - k)2 = r2 where h is the x coordinate of the center of the circle. where k is the y coordinate of the center of the circle. where x is the x coordinate of point (x,y) on the edge of the circle. where y is the y coordinate of point (x,y) on the edge of the circle. Additional assistance here: http://www.mathwarehouse.com/geometry/circle/equation-of-a-circle.php
How do you write an equation for a circle with a center?
Equation of any circle, with any radius, and its center at any point: [ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2
Table to Linear Equation?
You get the linear equation from a table by: Seeing the difference between the y coordinates and that should give you slope. Then find the point where x = 0 and at that point the y coordinate associated with the x is the y intercept and at the point where y = 0 the x coordinate associated is the x intercept. apply the y intercept and slope to the equation y = mx + c with m being the slope and c being the y intercept
