To find the x-coordinate in an equation, you typically set the equation equal to zero and solve for x. For example, if you have a quadratic equation like (ax^2 + bx + c = 0), you can use methods such as factoring, completing the square, or applying the quadratic formula (x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}). If the equation is linear, simply rearrange it to isolate x. Always ensure to check your solution by substituting back into the original equation.
To find the vertex of a parabola in standard form, which is given by the equation ( y = ax^2 + bx + c ), you can use the formula for the x-coordinate of the vertex: ( x = -\frac{b}{2a} ). Once you have the x-coordinate, substitute it back into the original equation to find the corresponding y-coordinate. The vertex will then be at the point ( (x, y) ).
Once you calculate the X coordinate using the axis of symmetry (X=-b/2a), you plug that value in for all of the X's in the equation of the parabola. You then solve the equation for the value of Y.
To find the vertex of a quadratic equation in standard form, (y = ax^2 + bx + c), you can use the vertex formula. The x-coordinate of the vertex is given by (x = -\frac{b}{2a}). Once you have the x-coordinate, substitute it back into the equation to find the corresponding y-coordinate. The vertex is then the point ((-\frac{b}{2a}, f(-\frac{b}{2a}))).
By solving the simultaneous equations the values of x and y should be equal to the given coordinate
To find the vertex of a quadratic equation in the form (y = ax^2 + bx + c), you can use the formula (x = -\frac{b}{2a}) to determine the x-coordinate of the vertex. Once you have the x-coordinate, substitute it back into the equation to find the corresponding y-coordinate. The vertex is then the point ((x, y)) on the graph. For graphs of other types of functions, the vertex may need to be identified through other methods, such as completing the square or analyzing the graph's shape.
To find the vertex of a parabola in standard form, which is given by the equation ( y = ax^2 + bx + c ), you can use the formula for the x-coordinate of the vertex: ( x = -\frac{b}{2a} ). Once you have the x-coordinate, substitute it back into the original equation to find the corresponding y-coordinate. The vertex will then be at the point ( (x, y) ).
Once you calculate the X coordinate using the axis of symmetry (X=-b/2a), you plug that value in for all of the X's in the equation of the parabola. You then solve the equation for the value of Y.
plug the x coordinate in the x part of the equation and plug the y coordinate in the y's part of the equation and solve
To find the vertex of a quadratic equation in standard form, (y = ax^2 + bx + c), you can use the vertex formula. The x-coordinate of the vertex is given by (x = -\frac{b}{2a}). Once you have the x-coordinate, substitute it back into the equation to find the corresponding y-coordinate. The vertex is then the point ((-\frac{b}{2a}, f(-\frac{b}{2a}))).
By solving the simultaneous equations the values of x and y should be equal to the given coordinate
To find the vertex of a quadratic equation in the form (y = ax^2 + bx + c), you can use the formula (x = -\frac{b}{2a}) to determine the x-coordinate of the vertex. Once you have the x-coordinate, substitute it back into the equation to find the corresponding y-coordinate. The vertex is then the point ((x, y)) on the graph. For graphs of other types of functions, the vertex may need to be identified through other methods, such as completing the square or analyzing the graph's shape.
You must first solve the equation for x, find the midpoint between the two x coordinates and substitute it into the equation to find the y coordinate I.E. If your equation was y=x^2+4x-5 1. Factorise the Equation and solve for x. x^2+4x-5 = (x+5)(x-1) So x+5=0 x = 0 - 5 x=-5 And x-1=0 x = 0 + 1 x = 1 So x = -5,1 Find the mid point/average: (-5+1)/2 = -2 So the x coordinate of the vertex is -2. Substitute this into the equation x^2+4x-5: (-2)^2 + 4*(-2) - 5 = 4 - 8 - 5 = -9 So the Coordinate of the vertex is (-2,-9). Hope this Helps, message me if you want more info.
To find the x-coordinate of the vertex in the quadratic equation ( y = x^2 + 6x - 2 ), you can use the formula ( x = -\frac{b}{2a} ), where ( a = 1 ) and ( b = 6 ). Plugging in the values, ( x = -\frac{6}{2 \times 1} = -3 ). Therefore, the x-coordinate of the vertex is ( -3 ).
The equation that represents the function where the y-coordinate is 18 times the x-coordinate is ( y = 18x ). In this linear equation, for every unit increase in ( x ), the value of ( y ) increases by 18 times that amount. This signifies a direct proportionality between ( y ) and ( x ) with a slope of 18.
The x-intercept of a graph is the point where the y-coordinate is 0. It represents the value of x at which the graph intersects the x-axis. To find the x-intercept, you can set the equation of the graph equal to zero and solve for x.
To find the vertex of a parabola given its equation in standard form (y = ax^2 + bx + c), you can use the formula for the x-coordinate of the vertex: (x = -\frac{b}{2a}). Once you have the x-coordinate, substitute it back into the equation to find the corresponding y-coordinate. Thus, the vertex can be expressed as the point ((-\frac{b}{2a}, f(-\frac{b}{2a}))). For parabolas in vertex form (y = a(x-h)^2 + k), the vertex is simply the point ((h, k)).
Yes, the coordinates for the vertex of a quadratic function in the form (y = ax^2 + bx + c) can be found using the formula (x = -\frac{b}{2a}) to determine the x-coordinate. Once you have the x-coordinate, substitute it back into the original equation to find the corresponding y-coordinate. This gives you the vertex in the form ((x, y)).