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To find the x-coordinate in an equation, you typically set the equation equal to zero and solve for x. For example, if you have a quadratic equation like (ax^2 + bx + c = 0), you can use methods such as factoring, completing the square, or applying the quadratic formula (x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}). If the equation is linear, simply rearrange it to isolate x. Always ensure to check your solution by substituting back into the original equation.
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How do you find the y-coordinate vertex of a parabola?
Once you calculate the X coordinate using the axis of symmetry (X=-b/2a), you plug that value in for all of the X's in the equation of the parabola. You then solve the equation for the value of Y.
How do you find the vertex of an equation in standard form?
To find the vertex of a quadratic equation in standard form, (y = ax^2 + bx + c), you can use the vertex formula. The x-coordinate of the vertex is given by (x = -\frac{b}{2a}). Once you have the x-coordinate, substitute it back into the equation to find the corresponding y-coordinate. The vertex is then the point ((-\frac{b}{2a}, f(-\frac{b}{2a}))).
How do you find equation when 2 equations and 1 coordinate is given?
By solving the simultaneous equations the values of x and y should be equal to the given coordinate
Which equation represents the function where the y-coordinate is 18 times the x coordinate?
The equation that represents the function where the y-coordinate is 18 times the x-coordinate is ( y = 18x ). In this linear equation, for every unit increase in ( x ), the value of ( y ) increases by 18 times that amount. This signifies a direct proportionality between ( y ) and ( x ) with a slope of 18.
Which value represents the x-coordinate of the vertex in the equation y xsquared 6x - 2?
To find the x-coordinate of the vertex in the quadratic equation ( y = x^2 + 6x - 2 ), you can use the formula ( x = -\frac{b}{2a} ), where ( a = 1 ) and ( b = 6 ). Plugging in the values, ( x = -\frac{6}{2 \times 1} = -3 ). Therefore, the x-coordinate of the vertex is ( -3 ).
How do you find the y-coordinate vertex of a parabola?
Once you calculate the X coordinate using the axis of symmetry (X=-b/2a), you plug that value in for all of the X's in the equation of the parabola. You then solve the equation for the value of Y.
How can you determine if an ordered pair is a solution to an equation?
plug the x coordinate in the x part of the equation and plug the y coordinate in the y's part of the equation and solve
How do you find the vertex of an equation in standard form?
To find the vertex of a quadratic equation in standard form, (y = ax^2 + bx + c), you can use the vertex formula. The x-coordinate of the vertex is given by (x = -\frac{b}{2a}). Once you have the x-coordinate, substitute it back into the equation to find the corresponding y-coordinate. The vertex is then the point ((-\frac{b}{2a}, f(-\frac{b}{2a}))).
How do you find equation when 2 equations and 1 coordinate is given?
By solving the simultaneous equations the values of x and y should be equal to the given coordinate
Which equation represents the function where the y-coordinate is 18 times the x coordinate?
The equation that represents the function where the y-coordinate is 18 times the x-coordinate is ( y = 18x ). In this linear equation, for every unit increase in ( x ), the value of ( y ) increases by 18 times that amount. This signifies a direct proportionality between ( y ) and ( x ) with a slope of 18.
How do you find the vertex of the parabola associated with a quadratic equation?
You must first solve the equation for x, find the midpoint between the two x coordinates and substitute it into the equation to find the y coordinate I.E. If your equation was y=x^2+4x-5 1. Factorise the Equation and solve for x. x^2+4x-5 = (x+5)(x-1) So x+5=0 x = 0 - 5 x=-5 And x-1=0 x = 0 + 1 x = 1 So x = -5,1 Find the mid point/average: (-5+1)/2 = -2 So the x coordinate of the vertex is -2. Substitute this into the equation x^2+4x-5: (-2)^2 + 4*(-2) - 5 = 4 - 8 - 5 = -9 So the Coordinate of the vertex is (-2,-9). Hope this Helps, message me if you want more info.
Which value represents the x-coordinate of the vertex in the equation y xsquared 6x - 2?
To find the x-coordinate of the vertex in the quadratic equation ( y = x^2 + 6x - 2 ), you can use the formula ( x = -\frac{b}{2a} ), where ( a = 1 ) and ( b = 6 ). Plugging in the values, ( x = -\frac{6}{2 \times 1} = -3 ). Therefore, the x-coordinate of the vertex is ( -3 ).
The of a graph is the point where the y-coordinate is 0.?
The x-intercept of a graph is the point where the y-coordinate is 0. It represents the value of x at which the graph intersects the x-axis. To find the x-intercept, you can set the equation of the graph equal to zero and solve for x.
How do you get the answer for a linear equation if the equation is in y equals mx plus b?
Well, you take y=mx+b and you fill in the numbers M= slope y= y-coordinate x= x-coordinate
How do you find the vertexof a parabola?
To find the vertex of a parabola given its equation in standard form (y = ax^2 + bx + c), you can use the formula for the x-coordinate of the vertex: (x = -\frac{b}{2a}). Once you have the x-coordinate, substitute it back into the equation to find the corresponding y-coordinate. Thus, the vertex can be expressed as the point ((-\frac{b}{2a}, f(-\frac{b}{2a}))). For parabolas in vertex form (y = a(x-h)^2 + k), the vertex is simply the point ((h, k)).
Do you have find the croodinates for the vertex for the quadratic function?
Yes, the coordinates for the vertex of a quadratic function in the form (y = ax^2 + bx + c) can be found using the formula (x = -\frac{b}{2a}) to determine the x-coordinate. Once you have the x-coordinate, substitute it back into the original equation to find the corresponding y-coordinate. This gives you the vertex in the form ((x, y)).
A vertical line in an x-y coordinate system?
A vertical line in the xy coordinate plane would represent the line of an equation such as x = 1 or x = -4.
