Once you calculate the X coordinate using the axis of symmetry (X=-b/2a), you plug that value in for all of the X's in the equation of the parabola. You then solve the equation for the value of Y.
By solving the simultaneous equations the values of x and y should be equal to the given coordinate
Well, you take y=mx+b and you fill in the numbers M= slope y= y-coordinate x= x-coordinate
A vertical line in the xy coordinate plane would represent the line of an equation such as x = 1 or x = -4.
Assuming 6 refers to the value of x, the y coordinate is 1
Once you calculate the X coordinate using the axis of symmetry (X=-b/2a), you plug that value in for all of the X's in the equation of the parabola. You then solve the equation for the value of Y.
plug the x coordinate in the x part of the equation and plug the y coordinate in the y's part of the equation and solve
By solving the simultaneous equations the values of x and y should be equal to the given coordinate
You must first solve the equation for x, find the midpoint between the two x coordinates and substitute it into the equation to find the y coordinate I.E. If your equation was y=x^2+4x-5 1. Factorise the Equation and solve for x. x^2+4x-5 = (x+5)(x-1) So x+5=0 x = 0 - 5 x=-5 And x-1=0 x = 0 + 1 x = 1 So x = -5,1 Find the mid point/average: (-5+1)/2 = -2 So the x coordinate of the vertex is -2. Substitute this into the equation x^2+4x-5: (-2)^2 + 4*(-2) - 5 = 4 - 8 - 5 = -9 So the Coordinate of the vertex is (-2,-9). Hope this Helps, message me if you want more info.
Well, you take y=mx+b and you fill in the numbers M= slope y= y-coordinate x= x-coordinate
A vertical line in the xy coordinate plane would represent the line of an equation such as x = 1 or x = -4.
Assuming 6 refers to the value of x, the y coordinate is 1
(x - h)2 + (y - k)2 = r2 where h is the x coordinate of the center of the circle. where k is the y coordinate of the center of the circle. where x is the x coordinate of point (x,y) on the edge of the circle. where y is the y coordinate of point (x,y) on the edge of the circle. Additional assistance here: http://www.mathwarehouse.com/geometry/circle/equation-of-a-circle.php
Equation of any circle, with any radius, and its center at any point: [ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2
You get the linear equation from a table by: Seeing the difference between the y coordinates and that should give you slope. Then find the point where x = 0 and at that point the y coordinate associated with the x is the y intercept and at the point where y = 0 the x coordinate associated is the x intercept. apply the y intercept and slope to the equation y = mx + c with m being the slope and c being the y intercept
The y intercept will be where the x-coordinate is zero, so set x=0 in the equation and you have: 0 + y = -9, or y = -9. Coordinate (0,-9)
All points whose y-coordinate is twice its x-coordinate.