It depends on what other information you are given. If you are given the x-component and the angle, then you can still use trig by doing the following.
Tan(angle)=y/x
If you do not have the x component, then you will need to use other kinematic equations to find the answer. The different ways to find this information are too numerous to list out, but I will give an example of a common one.
If you are given the horizontal distance and time the object flies, use
d=vt
to find the x component of velocity, then use the first strategy.
Given a vector, speed is the magnitude of the velocity vector, |v|. Consider vector V= IVx + JVy + KVz the magnitude is |V| = ( Vx2 + Vy2 + Vz2)1/2
If they are parallel, you can add them algebraically to get a resultant vector. Then you can resolve the resultant vector to obtain the vector components.
The magnitude alone can't tell you anything about its components. You also need to know its direction.
We get the Unit Vector
That's it! You know everything there is to know about it. It's not as if you have to wander through a crowd of vectors and find one that matches the description. "Find the vector" means figure out its magnitude and direction. If the problem already gave you the magnitude and direction, then it's unlikely that it's asking you to 'find' that same vector.
Divide the vector by it's length (magnitude).
Given a vector, speed is the magnitude of the velocity vector, |v|. Consider vector V= IVx + JVy + KVz the magnitude is |V| = ( Vx2 + Vy2 + Vz2)1/2
If they are parallel, you can add them algebraically to get a resultant vector. Then you can resolve the resultant vector to obtain the vector components.
The magnitude alone can't tell you anything about its components. You also need to know its direction.
We get the Unit Vector
That's it! You know everything there is to know about it. It's not as if you have to wander through a crowd of vectors and find one that matches the description. "Find the vector" means figure out its magnitude and direction. If the problem already gave you the magnitude and direction, then it's unlikely that it's asking you to 'find' that same vector.
The magnitude of a vector is a geometrical value for hypotenuse.. The magnitude is found by taking the square root of the i and j components.
To find the magnitude of the resultant vector, you can use the Pythagorean theorem. Simply square the x-component, square the y-component, add them together, and then take the square root of the sum. This will give you the magnitude of the resultant vector.
One component = (magnitude) times (cosine of the angle).Other component = (magnitude) times (sine of the angle).In order to decide which is which, we have to know the angle with respect to what.
If you assume the vector is only in two dimensions, you can find the missing y-component with Pythagoras' Theorem: y = square root of (magnitude2 - x2).
Use trigonometry.
The magnitude of a vector can be found by taking the square root of each of the vector components squared. For example, if you had the vector 3i+4j, to find the magnitude, you take sqrt ( 3²+4² ) To get: sqrt ( 9+16 ) sqrt ( 25 ) = 5 Works the same in 3D or more, just put all the vector components in.