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Since theta is in the second quadrant, sin(theta) is positive.

sin2(theta) = 1 - cos2(theta) = 0.803

So sin(theta) = +sqrt(0.803) = 0.896.

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Q: If costheta -.444 with theta in quadrant 2 find sintheta?
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How do you find tan-theta when sin-theta equals -0.5736 and cos-theta is greater than 0?

-0.5736


What is a quadrantal angle?

A Quadrantal angle is an angle that is not in Quadrant I. Consider angle 120. You want to find cos(120) . 120 lies in quadrant II. Also, 120=180-60. So, it is enough to find cos(60) and put the proper sign. cos(60)=1/2. Cosine is negative in quadrant II, Therefore, cos(120) = -1/2.


Why only cos theta is used in vector functions?

It's not. Cos(Θ) only gives you the x-component of a vector. In order to find its y-component, you also need to use sin(Θ).


How find sin theta?

Sin (theta) can most easily be found on a scientific calculator. You can also approximate it with Taylor's Series... sin(x) = SummationN=0toInfinity (-1N / (2N + 1) !) (x(2N+1))) sin(x) = x - x3/3! + x5/5! - x7/7! + ... Using only the four terms above, you can approximate sin(x) within about 0.000003 in the interval x = [-1, +1].


Is theta similar to 'x'?

it depends...theta:theta is usually the letter given to any angle in the triangle (the letter theta is from the greek alphabet). usually in trigonometry you would use it when using SOHCAHTOA (sin=opposite/hypotenuse; cos=adjacent/hypotenuse; tan=opposite/adjacent) e.g. the sun is at an angle of 30°. if the shadow's length is 40m, find the length of the flagpole.tan30=h/40tanθ=opp/adj40xtan30=hh=23.09m-'opposite' (opp)is the opposite side from the angle you are trying to find out-'adjacent' (adj)is the side next to the angle you are trying to find out-'hypotenuse' (hyp)is also next to the angle you are trying to find out, but it is also opposite the right angle and it is the longest sidex:'x' is usually used to represent a length (either the base, height or hypotenuse). using SOHCAHTOA it would be either the opposite, adjacent or hypotenuse. using the example above x could substitute hthe difference is that theta is used for the angles and x is for the other measurements(length or distance). i don't think that there similar but thats just me...

Related questions

If costheta equals frac2sqrt6 in Quadrant 1 then find tantheta?

tan theta = sqrt(2)/2 = 1/sqrt(2).


If tan Theta equals 2 with Theta in Quadrant 3 find cot Theta?

Cotan(theta) is the reciprocal of the tan(theta). So, cot(theta) = 1/2.


How do you find tan-theta when sin-theta equals -0.5736 and cos-theta is greater than 0?

-0.5736


How do you find the theta of a triangle?

The answer depends on what theta represents!


How do you find perimeter of quadrant?

perimeter of what quadrant?


Should we find cos theta if sec theta equals -10?

No.


If tansqtheta plus 5tantheta0 find the value of tantheta plus cottheta?

tan2(theta) + 5*tan(theta) = 0 => tan(theta)*[tan(theta) + 5] = 0=> tan(theta) = 0 or tan(theta) = -5If tan(theta) = 0 then tan(theta) + cot(theta) is not defined.If tan(theta) = -5 then tan(theta) + cot(theta) = -5 - 1/5 = -5.2


An angle is 12 degrees more than its supplement Find the angle?

96 degrees Let theta represent the measure of the angle we are trying to find and theta' represent the measure of its supplement. From the problem, we know: theta=theta'+12 Because supplementary angles sum to 180 degrees, we also know: theta+theta'=180 Substituting the value from theta in the first equation into the second, we get: (theta'+12)+theta'=180 2*theta'+12=180 2*theta'=180-12=168 theta'=168/2=84 Substituting this value for theta' back into the first equation, we get: theta+84=180 theta=180-84=96


Find all angles in the interval 0 360 satisfying the equation cos theta equals 0.7902?

cos(theta) = 0.7902 arcos(0.7902) = theta = 38 degrees you find complimentary angles


What quadrant would you find pi over 5 in?

Pi / 5 would be in Quadrant I.


How can you find the length of an arc with the radius known?

The length of the arc is r*theta where r is the radius and theta the angle subtended by the arc at the centre of the circle. If you do not know theta (or cannot derive it), you cannot find the length of the arc.


How do you find the sine of an angle?

sine[theta]=opposite/hypotenuse=square root of (1-[cos[theta]]^2)