Since theta is in the second quadrant, sin(theta) is positive.
sin2(theta) = 1 - cos2(theta) = 0.803
So sin(theta) = +sqrt(0.803) = 0.896.
-0.5736
A Quadrantal angle is an angle that is not in Quadrant I. Consider angle 120. You want to find cos(120) . 120 lies in quadrant II. Also, 120=180-60. So, it is enough to find cos(60) and put the proper sign. cos(60)=1/2. Cosine is negative in quadrant II, Therefore, cos(120) = -1/2.
It's not. Cos(Θ) only gives you the x-component of a vector. In order to find its y-component, you also need to use sin(Θ).
Sin (theta) can most easily be found on a scientific calculator. You can also approximate it with Taylor's Series... sin(x) = SummationN=0toInfinity (-1N / (2N + 1) !) (x(2N+1))) sin(x) = x - x3/3! + x5/5! - x7/7! + ... Using only the four terms above, you can approximate sin(x) within about 0.000003 in the interval x = [-1, +1].
it depends...theta:theta is usually the letter given to any angle in the triangle (the letter theta is from the greek alphabet). usually in trigonometry you would use it when using SOHCAHTOA (sin=opposite/hypotenuse; cos=adjacent/hypotenuse; tan=opposite/adjacent) e.g. the sun is at an angle of 30°. if the shadow's length is 40m, find the length of the flagpole.tan30=h/40tanθ=opp/adj40xtan30=hh=23.09m-'opposite' (opp)is the opposite side from the angle you are trying to find out-'adjacent' (adj)is the side next to the angle you are trying to find out-'hypotenuse' (hyp)is also next to the angle you are trying to find out, but it is also opposite the right angle and it is the longest sidex:'x' is usually used to represent a length (either the base, height or hypotenuse). using SOHCAHTOA it would be either the opposite, adjacent or hypotenuse. using the example above x could substitute hthe difference is that theta is used for the angles and x is for the other measurements(length or distance). i don't think that there similar but thats just me...
tan theta = sqrt(2)/2 = 1/sqrt(2).
Cotan(theta) is the reciprocal of the tan(theta). So, cot(theta) = 1/2.
-0.5736
The answer depends on what theta represents!
perimeter of what quadrant?
No.
tan2(theta) + 5*tan(theta) = 0 => tan(theta)*[tan(theta) + 5] = 0=> tan(theta) = 0 or tan(theta) = -5If tan(theta) = 0 then tan(theta) + cot(theta) is not defined.If tan(theta) = -5 then tan(theta) + cot(theta) = -5 - 1/5 = -5.2
96 degrees Let theta represent the measure of the angle we are trying to find and theta' represent the measure of its supplement. From the problem, we know: theta=theta'+12 Because supplementary angles sum to 180 degrees, we also know: theta+theta'=180 Substituting the value from theta in the first equation into the second, we get: (theta'+12)+theta'=180 2*theta'+12=180 2*theta'=180-12=168 theta'=168/2=84 Substituting this value for theta' back into the first equation, we get: theta+84=180 theta=180-84=96
cos(theta) = 0.7902 arcos(0.7902) = theta = 38 degrees you find complimentary angles
Pi / 5 would be in Quadrant I.
The length of the arc is r*theta where r is the radius and theta the angle subtended by the arc at the centre of the circle. If you do not know theta (or cannot derive it), you cannot find the length of the arc.
sine[theta]=opposite/hypotenuse=square root of (1-[cos[theta]]^2)