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How do you find tan-theta when sin-theta equals -0.5736 and cos-theta is greater than 0?
-0.5736
What is a quadrantal angle?
A Quadrantal angle is an angle that is not in Quadrant I. Consider angle 120. You want to find cos(120) . 120 lies in quadrant II. Also, 120=180-60. So, it is enough to find cos(60) and put the proper sign. cos(60)=1/2. Cosine is negative in quadrant II, Therefore, cos(120) = -1/2.
If the resultant of two equal forces is root2 times a single force find the angle between them?
If two equal forces ( F ) are acting at an angle ( \theta ), the resultant ( R ) can be calculated using the formula ( R = F \sqrt{2(1 + \cos\theta)} ). Given that the resultant is ( \sqrt{2} F ), we can set up the equation ( \sqrt{2} F = F \sqrt{2(1 + \cos\theta)} ). Dividing through by ( F ) (assuming ( F \neq 0 )), we have ( \sqrt{2} = \sqrt{2(1 + \cos\theta)} ). Squaring both sides gives ( 2 = 2(1 + \cos\theta) ), which simplifies to ( \cos\theta = 0 ). Therefore, the angle ( \theta ) between the two forces is ( 90^\circ ).
If the resultant of two vectors each of magnitide f is twice of magnitude F then angle bw?
If the resultant of two vectors, each of magnitude ( f ), is twice the magnitude ( F ), then the angle ( \theta ) between the two vectors can be determined using the formula for the resultant of two vectors: [ R = \sqrt{f^2 + f^2 + 2f^2 \cos \theta} ] Given that ( R = 2F ), we set ( R = 2f ) (assuming ( F = f )). This leads to the equation ( 4f^2 = 2f^2(1 + \cos \theta) ). Solving for ( \theta ), we find that ( \cos \theta = 0 ), which means ( \theta = 90^\circ ). Thus, the angle between the vectors is ( 90^\circ ).
What quadrant of the terminal side and the sign of the function when cot is-495 degrees?
To find the quadrant and sign of the cotangent function for -495 degrees, first, convert it to a positive angle by adding 360 degrees until the angle is within the standard range. -495 + 720 = 225 degrees. The angle 225 degrees is in the third quadrant, where both sine and cosine are negative, making cotangent (which is the ratio of cosine to sine) positive. Thus, cot(-495 degrees) is positive and located in the third quadrant.
If costheta equals frac2sqrt6 in Quadrant 1 then find tantheta?
tan theta = sqrt(2)/2 = 1/sqrt(2).
If tan Theta equals 2 with Theta in Quadrant 3 find cot Theta?
Cotan(theta) is the reciprocal of the tan(theta). So, cot(theta) = 1/2.
How do you find tan-theta when sin-theta equals -0.5736 and cos-theta is greater than 0?
-0.5736
How do you find the theta of a triangle?
The answer depends on what theta represents!
How do you find perimeter of quadrant?
perimeter of what quadrant?
Should we find cos theta if sec theta equals -10?
No.
If tansqtheta plus 5tantheta0 find the value of tantheta plus cottheta?
tan2(theta) + 5*tan(theta) = 0 => tan(theta)*[tan(theta) + 5] = 0=> tan(theta) = 0 or tan(theta) = -5If tan(theta) = 0 then tan(theta) + cot(theta) is not defined.If tan(theta) = -5 then tan(theta) + cot(theta) = -5 - 1/5 = -5.2
An angle is 12 degrees more than its supplement Find the angle?
96 degrees Let theta represent the measure of the angle we are trying to find and theta' represent the measure of its supplement. From the problem, we know: theta=theta'+12 Because supplementary angles sum to 180 degrees, we also know: theta+theta'=180 Substituting the value from theta in the first equation into the second, we get: (theta'+12)+theta'=180 2*theta'+12=180 2*theta'=180-12=168 theta'=168/2=84 Substituting this value for theta' back into the first equation, we get: theta+84=180 theta=180-84=96
What is cot theta 1.5 sin theta?
The expression "cot theta = 1.5 sin theta" can be rewritten using the definitions of trigonometric functions. Since cotangent is the reciprocal of tangent, we have cot(theta) = cos(theta) / sin(theta). Therefore, the equation becomes cos(theta) / sin(theta) = 1.5 sin(theta), leading to cos(theta) = 1.5 sin^2(theta). This relationship can be used to find specific values of theta that satisfy the equation.
Find all angles in the interval 0 360 satisfying the equation cos theta equals 0.7902?
cos(theta) = 0.7902 arcos(0.7902) = theta = 38 degrees you find complimentary angles
What quadrant would you find pi over 5 in?
Pi / 5 would be in Quadrant I.
How can you find the length of an arc with the radius known?
The length of the arc is r*theta where r is the radius and theta the angle subtended by the arc at the centre of the circle. If you do not know theta (or cannot derive it), you cannot find the length of the arc.
