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A Quadrantal angle is an angle that is not in Quadrant I. Consider angle 120. You want to find cos(120) . 120 lies in quadrant II. Also, 120=180-60. So, it is enough to find cos(60) and put the proper sign. cos(60)=1/2. Cosine is negative in quadrant II, Therefore, cos(120) = -1/2.
Tangent (theta) is cosine / sine, or Y / X.Tangent (theta) is 40 / 58Theta = 34.6 degreesSince we are dividing cosine by sine, the hypotenuse does not matter as it cancels out.
It's not. Cos(Θ) only gives you the x-component of a vector. In order to find its y-component, you also need to use sin(Θ).
Sin (theta) can most easily be found on a scientific calculator. You can also approximate it with Taylor's Series... sin(x) = SummationN=0toInfinity (-1N / (2N + 1) !) (x(2N+1))) sin(x) = x - x3/3! + x5/5! - x7/7! + ... Using only the four terms above, you can approximate sin(x) within about 0.000003 in the interval x = [-1, +1].
tan theta = sqrt(2)/2 = 1/sqrt(2).
Cotan(theta) is the reciprocal of the tan(theta). So, cot(theta) = 1/2.
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The answer depends on what theta represents!
perimeter of what quadrant?
No.
tan2(theta) + 5*tan(theta) = 0 => tan(theta)*[tan(theta) + 5] = 0=> tan(theta) = 0 or tan(theta) = -5If tan(theta) = 0 then tan(theta) + cot(theta) is not defined.If tan(theta) = -5 then tan(theta) + cot(theta) = -5 - 1/5 = -5.2
-1
96 degrees Let theta represent the measure of the angle we are trying to find and theta' represent the measure of its supplement. From the problem, we know: theta=theta'+12 Because supplementary angles sum to 180 degrees, we also know: theta+theta'=180 Substituting the value from theta in the first equation into the second, we get: (theta'+12)+theta'=180 2*theta'+12=180 2*theta'=180-12=168 theta'=168/2=84 Substituting this value for theta' back into the first equation, we get: theta+84=180 theta=180-84=96
cos(theta) = 0.7902 arcos(0.7902) = theta = 38 degrees you find complimentary angles
Pi / 5 would be in Quadrant I.
The length of the arc is r*theta where r is the radius and theta the angle subtended by the arc at the centre of the circle. If you do not know theta (or cannot derive it), you cannot find the length of the arc.