9*9*9 = 729 using the digits 1 to 9 and 2*9 using 10 and another digit. 749 in all.
(9/3 + 6)*1 = 9
If you have to use all four digits - 1349. If you can use them in a sum 9-4-3-1 = 1
(9+1)^(8+7-6-5-4+2+3) = 10^5 = 100,000
(987 + 13)(6 + 4) x 2 x 5 = 1000 x 10 x 10 = 100000
11-1-1 = 9
9*9*9 = 729 using the digits 1 to 9 and 2*9 using 10 and another digit. 749 in all.
(9/3 + 6)*1 = 9
Digits are from 1 to 9the sum of the 9 greatest digits is = 9+9+9+9+9+9+9+9+9 = 81the sum of the 9 lowest digits is = 1+1+1+1+1+1+1+1+1+1= 9and so :81 + 9 = 90
To get 900 using the digits 1 to 9 without repetition, you can multiply 9 by 100. This is because 9 times 100 equals 900. By using the digit 9 once and the digit 1 twice, you can achieve the desired result without repeating any digits.
If you have to use all four digits - 1349. If you can use them in a sum 9-4-3-1 = 1
987,654,321
(9+1)^(8+7-6-5-4+2+3) = 10^5 = 100,000
1/18
98756 999,998
i dont no
9+3-1