i dont no
Yuo can make only one combination of 30 digits using 30 digits.
If using the compressed format, where a byte holds two decimal digits (because only 4 bits are needed to make nine), so two bytes would be four decimal digits, the largest which is 9999.
9531
You cannot because there are no duplicate digits.
write the largest number you can make using each of the digits 7,1,0,2, and 9 just once
( ( 6 / 6 ) + 6) * 6
3*3*2*1 = 18 of them.
Yuo can make only one combination of 30 digits using 30 digits.
Yes
The four-digit numbers that can be formed using the digits 6, 7, 8, and 9, without repetition, are all the permutations of these four digits. There are 24 possible combinations, including numbers like 6789, 6798, 6879, and so on. Essentially, any arrangement of these four digits constitutes a valid four-digit number.
4 x 3 x 2 ie 24
Twelve of them.
9876 is the largest four digit number you can make if all the digits must be different.
If you have to use all four digits - 1349. If you can use them in a sum 9-4-3-1 = 1
61 is prime. You cannot make 61 by multiplying four digits.
If you use them only once each, you can make 15 combinations. 1 with all four digits, 4 with 3 digits, 6 with 2 digits, and 4 with 1 digit. There is also a combination containing no digits making 16 = 24 combinations from 4 elements.
456, 546 and 564 are three of the four possible even numbers.