If you have an angle of (pi/4+k*pi) or pi*(0.25+k) radians where k is an integer.
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The tangent-tangent angle is formed by two tangents drawn from a point outside a circle to points on the circle. To find the measure of the tangent-tangent angle, you take half the difference of the intercepted arcs. In this case, the arcs measure 135 degrees and 225 degrees. Therefore, the measure of the tangent-tangent angle is (\frac{1}{2} (225^\circ - 135^\circ) = \frac{1}{2} (90^\circ) = 45^\circ).
Zero. Tangent = sine/cosine. sin(0) = 0 and cos(0) = 1, so 0/1 = 0.
In the limit, a chord approaches a tangent, but is never actually a tangent. (In much the same way as 1/x approaches 0 as x increases, but is never actually 0.)In the limit, a chord approaches a tangent, but is never actually a tangent. (In much the same way as 1/x approaches 0 as x increases, but is never actually 0.)In the limit, a chord approaches a tangent, but is never actually a tangent. (In much the same way as 1/x approaches 0 as x increases, but is never actually 0.)In the limit, a chord approaches a tangent, but is never actually a tangent. (In much the same way as 1/x approaches 0 as x increases, but is never actually 0.)
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Reciprocal of tangent is '1 /tangent' or ' Cosine / Sine '
Cotangent is ' 1/tangent' or ' Cosine / Sine'.
-0.017455064928
1
The reciprocal of the tangent is the cotangent, or cot. We might write 1/tan = cot.
Zero. Tangent = sine/cosine. sin(0) = 0 and cos(0) = 1, so 0/1 = 0.
In the limit, a chord approaches a tangent, but is never actually a tangent. (In much the same way as 1/x approaches 0 as x increases, but is never actually 0.)In the limit, a chord approaches a tangent, but is never actually a tangent. (In much the same way as 1/x approaches 0 as x increases, but is never actually 0.)In the limit, a chord approaches a tangent, but is never actually a tangent. (In much the same way as 1/x approaches 0 as x increases, but is never actually 0.)In the limit, a chord approaches a tangent, but is never actually a tangent. (In much the same way as 1/x approaches 0 as x increases, but is never actually 0.)
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2/1
Yes.
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