The magnitude of cos(135°) is the same as that of cos(45°) [cos(180° - 135°)], and the sign is negative because it is in the second quadrant of the Cartesian plane, so it's the reciprocal of the negative square root of two, about -0.707.
The cosines of 2nd- and 3rd-quadrant angles are negative, and the sines of 3rd- and 4th-quadrant angles are negative.
The exact value of (\cos(40.7^\circ)) is not a simple rational number or a well-known trigonometric value. To find its numerical approximation, you can use a calculator, which gives (\cos(40.7^\circ) \approx 0.7578). For precise applications, it's best to use a calculator or software that can compute trigonometric functions.
Absolute value of -135 is 135.
-0.7071067812, roughly.
The inverse cos of 1 is equal to o degrees. You can find this answer by knowing what angle measurement has cos equal to a value of 1.
hi,the value of cos 60 is 1/2
cos(195) = -0.965925826289
tan(135 degrees) = negative 1.
negative one half
It is: cos(15) = (sq rt of 6+sq rt of 2)/4
The radical answer is sqrt(3)/2. (0.86602540378443864676372317075294)
The exact value is an irrational number, and can't be written on paper with digits.0.34202 is less than 0.000042 percent wrong.Cos(70 deg) is an irrational number and it is impossible to give its exact value.
cos(495) = cos(495-360) = cos(135) = -cos(180-135) = -cos(45) = -sqrt(1/2) or -1/sqrt(2)
1.25
Absolute value of -135 is 135.
-0.7071067812, roughly.
The inexact value of tan 330 is -0.577350, to six significant places. The exact value cannot be represented as a single number because it is a non terminating decimal. To represent it exactly, consider that tan x is sin x over cos x, and that sin 330 is -0.5 and cos 330 is square root of 0.75. As a result, the exact value of tan 330 is -0.5 divided by square root of 0.75.
1/squareroot2 ummm, yes, but be aware that square root 2 is an irrational number that has *no* exact value. So your question cannot be answered in the terms you asked it. You can use a calculator to get as much precision as you want, but never an *exact* answer.