17 = (4+2)*3 - 1
4 dvided by 2 minus 1 times 3
To get 1000 using the numbers 1, 2, 3, and 4 only once in an equation, you can use the following mathematical expression: (4 x 2 x 3 x 1) x (4 + 2 + 3 + 1) = 1000. This equation involves multiplication and addition operations using all four numbers exactly once to achieve the desired result of 1000.
It can be: 2*3+4+1 = 11
only using the numbers once
17 = (4+2)*3 - 1
4x4x3+2
By the uniqueness of numbers, the only number for 1234 is 1234 itself.
What is 4 divided by 1,234
4(2+3)-1=19
The answer is 34(1)^2.
How about: 2*(1+3+4) = 16
4 dvided by 2 minus 1 times 3
To get 1000 using the numbers 1, 2, 3, and 4 only once in an equation, you can use the following mathematical expression: (4 x 2 x 3 x 1) x (4 + 2 + 3 + 1) = 1000. This equation involves multiplication and addition operations using all four numbers exactly once to achieve the desired result of 1000.
18 = (4 × 3) + (2 × 1)
It can be: 2*3+4+1 = 11
2x4x3 is 24+1 is 25, x4 is 100. 2x3 is 6+4 is 10. 10*100 is 1000. That is one way. All ways require using the numbers more than once