x2 + 8x = x(x+8)
x + 4
x2 + 8x = -15 x2 + 8x + 15 = 0 since 15 = 5 x 3 and 5 + 3 = 8, then (x + 5)(x + 3) = 0 x + 5 = 0 or x + 3 = 0 x = -5 or x = -3
(-4,-1)
(x+5)(x+3)
x2 + 8x + 15 = (x + 3)(x + 5)
x2-8x+15 = (x-3)(x-5)
That does not factor neatly.
x2 + 8x = x(x+8)
x + 4
x2 + 8x = -15 x2 + 8x + 15 = 0 since 15 = 5 x 3 and 5 + 3 = 8, then (x + 5)(x + 3) = 0 x + 5 = 0 or x + 3 = 0 x = -5 or x = -3
x² + 8x + 15 = (x + 5)(x + 3)
x2 + 8x + 12 = (x + 6) (x + 2)
(-4,-1)
(x + 6)(x + 2)
x2 - 8x + 32 = 0 (assuming)you can factor or use the quadratic equation.I recommend the quadratic equation.
No because the discriminant is less than zero.