The derivative of a function is the function's tangent function.
So, d(y)/dx = d(2tan(2x))/dx = 2*d(tan(2x))/dx = 2*d(tan(u))/du*du/dx, where u=2x, = 2*sec2(2x)*d(2x)/dx = 4*sec2(2x)*d(x)/dx = 4*sec2(2x)
Now just make a plot for y = 4*sec2(2x) and you got your tangent function.
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f(x)= tan2(x) f'(x)= 2tan(x)*sec2(x)
(90/2tan*Dia*1.5*25.4) (45/2tan*Dia*1.5*25.4) u will obtain Ur answer in (mm)
If 2b a plus c, then we can say that 3tan A 2tan c = 21.
L=length of side the square root of (L/2tan(pi/5))2+L2X5 Hope this helps!
f'(x) = 1/tan(x) * sec^2(x) where * means multiply and ^ means to the power of. = cot(x) * sec^2(x) f''(x) = f'(cot(x)*sec^2(x) + cot(x)*f'[sec^2(x)] = -csc^2(x)*sec^2(x) + cot(x)*2tan(x)sec^2(x) = sec^2(x) [cot(x)-csc^2(x)] +2tan(x)cot(x) = sec^2(x) [cot(x)-csc^2(x)] +2