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The derivative of a function is the function's tangent function.
So, d(y)/dx = d(2tan(2x))/dx = 2*d(tan(2x))/dx = 2*d(tan(u))/du*du/dx, where u=2x, = 2*sec2(2x)*d(2x)/dx = 4*sec2(2x)*d(x)/dx = 4*sec2(2x)
Now just make a plot for y = 4*sec2(2x) and you got your tangent function.
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What is the derivative of tangent squared?
f(x)= tan2(x) f'(x)= 2tan(x)*sec2(x)
How to calculate a 90 degree elbow center?
(90/2tan*Dia*1.5*25.4) (45/2tan*Dia*1.5*25.4) u will obtain Ur answer in (mm)
Evaluate sin30 plus cos60-2tan45?
using the unit circle, sin 30 + cos 60 - 2tan 45 can be solved as follows: = sin 30 + cos 60 - 2tan 45 = [1/2] + [1/2] - [2(1)] = 1 - 2 = -1
If 2b a plus c then show that 3tan A 2 tan c 2 1?
If 2b a plus c, then we can say that 3tan A 2tan c = 21.
How do you find the area of a pentagon with the same side lenghs?
L=length of side the square root of (L/2tan(pi/5))2+L2X5 Hope this helps!
What is the derivative of tangent squared?
f(x)= tan2(x) f'(x)= 2tan(x)*sec2(x)
What value of x satisfies the equation 2tan x plus 2square root3 equals 3square root3?
2tan(x) + 2√3 = 3√3 2tan(x) = √3 tan(x) = √3 / 2 x = atan(√3 / 2) x ≈ 0.71372437894476563082
How to calculate a 90 degree elbow center?
(90/2tan*Dia*1.5*25.4) (45/2tan*Dia*1.5*25.4) u will obtain Ur answer in (mm)
What is the derivative of sec squared x?
derivative of sec2(x)=2tan(x)sec2(x)
Evaluate sin30 plus cos60-2tan45?
using the unit circle, sin 30 + cos 60 - 2tan 45 can be solved as follows: = sin 30 + cos 60 - 2tan 45 = [1/2] + [1/2] - [2(1)] = 1 - 2 = -1
What is the apothem length of a 3D cube?
a=apothem; a = s/2 or a=s/[2tan(180/4)] Use either of the two if the measurement of the side is given.
If 2b a plus c then show that 3tan A 2 tan c 2 1?
If 2b a plus c, then we can say that 3tan A 2tan c = 21.
How do you find the area of a pentagon with the same side lenghs?
L=length of side the square root of (L/2tan(pi/5))2+L2X5 Hope this helps!
What is the second derivative of ln(tan(x))?
f'(x) = 1/tan(x) * sec^2(x) where * means multiply and ^ means to the power of. = cot(x) * sec^2(x) f''(x) = f'(cot(x)*sec^2(x) + cot(x)*f'[sec^2(x)] = -csc^2(x)*sec^2(x) + cot(x)*2tan(x)sec^2(x) = sec^2(x) [cot(x)-csc^2(x)] +2tan(x)cot(x) = sec^2(x) [cot(x)-csc^2(x)] +2
Integral lnx2 1?
If you mean integral ln(x2+1)dx, it is 2tan-1(x)+x[ln(x2+1)-2]. To find this and other integrals, go to http://integrals.wolfram.com/index.jsp?expr=ln(x^2%2B1)&random=false It can solve nearly every integral I've encountered.
How do you find the surface area of a pentagon based pyramid with slant height of 11 meters and a side length of 3 meters?
Calculate the area of the 5 individual triangles that make the pyramid and the area of the pentagonal base and add these six areas together. Atriangle = 1/3 Base x Height Apentagon = (Perimeter x Apothem)/2 Apothem = side length/(2Tan(∏/Number of sides))
Can you prove that area formula of hexagon?
Assume regular hexagon of side L. Split the hexagon into 6 equilateral triangles. (A sketch would help here) You need to find the height of the triangle to find it's area. Split the triangle in half with a vertical line. You now have 2 right angle triangles of base L/2 height h. Top angle 30 degrees, bottom angle 60 degrees. L/(2h) = tan 30 h = L/(2tan 30) h = root 3 L/2 Area of 1 equilateral triangle = 1/2 x L x h = (root 3 x L2)/4 Area of hexagon = 6x(root 3 x L2)/4 Area of hexagon = 3x(root 3 x L2)/2
