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What is the derivative of 5secx?
You can take out any constant from a derivative. In other words, this is the same as 5 times the derivative of sec x.
Derivative of x3?
the derivative of 3x is 3 the derivative of x cubed is 3 times x squared
What is the derivative of x squared times sin sqaured x?
2xsin2x+2x2sinxcosx
What is the derivative of sec5X?
The idea is to use the chain rule. Look up the derivative of sec x, and just replace "x" with "5x". Then multiply that with the derivative of 5x.
What is the derivative of secxtanx?
d/dx(uv)=u*dv/dx+v*du/dxd/dx(secxtanx)=secx*[d/dx(tanx)]+tanx*[d/dx(secx)]-The derivative of tanx is:d/dx(tan u)=[sec(u)]2*d/dx(u)d/dx(tan x)=[sec(x)]2*d/dx(x)d/dx(tan x)=[sec(x)]2*(1)d/dx(tan x)=(sec(x))2=sec2(x)-The derivative of secx is:d/dx(sec u)=[sec(u)tan(u)]*d/dx(u)d/dx(sec x)=[sec(x)tan(x)]*d/dx(x)d/dx(sec x)=[sec(x)tan(x)]*(1)d/dx(sec x)=sec(x)tan(x)d/dx(secxtanx)=secx*[sec2(x)]+tanx*[sec(x)tan(x)]d/dx(secxtanx)=sec3(x)+sec(x)tan2(x)
What is the derivative of secant x?
The derivative of sec(x) is sec(x) tan(x).
What is the second derivitive of sec x?
Write sec x as a function of sines and cosines (in this case, sec x = 1 / cos x). Then use the division formula to take the first derivative. Take the derivative of the first derivative to get the second derivative. Reminder: the derivative of sin x is cos x; the derivative of cos x is - sin x.
What is the derivative of y equals tan x?
Given y = tan x: dy/dx = sec^2 x(secant of x squared)
What is the derivative of 5secx?
You can take out any constant from a derivative. In other words, this is the same as 5 times the derivative of sec x.
What is the derivative of y equals sec x?
sec(x)tan(x)
What is the derivative of tangent squared?
f(x)= tan2(x) f'(x)= 2tan(x)*sec2(x)
Derivative of x3?
the derivative of 3x is 3 the derivative of x cubed is 3 times x squared
What is the anti derivative of 2x?
x squared
What is the derivative of 5x squared?
10 x
What is the antiderivative squared 0 9X18 squared X 17 X 18?
Let k = 0 9x18 squared x 17 x 18 k is a constant. Its anti-derivative is kx + C, where C is a constant. The anti-derivative squared is (kx+ C) squared.
What is the derivative of tangent?
the derivative of tangent dy/dx [ tan(u) ]= [sec^(2)u]u' this means that the derivative of tangent of u is secant squared u times the derivative of u.
What is the derivative of the square root of one minus x squared?
The derivative, with respect to x, is -x/sqrt(1-x2)
