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I think you want: √300 = √(100 x 3) = √100 x √3 = 10√3
Let Q be the quantity of 80% solution required then (300 - Q) is the quantity of 30% solution as together the two solutions must equal 300. Then, [80 x Q] + [30 x (300 - Q)] = [40 x 300] 80Q + 9000 - 30Q = 12000 50Q = 3000 Q = 60...........which means (300 - Q) = 240 60ml of 80% acid solution + 240ml of 30% solution produces 300ml of 40% solution.
No, 18.75 is the solution.
The statement "300 is between 100 and 400" is equivalent to: 100 < 300 < 400 Or the equivalent: 300 > 100 AND 300 < 400. If you check these statements and see that they are true, then 300 is between the two numbers.
The pair of square numbers that has a difference of 300 can be found by solving the equation (x^2 - y^2 = 300), which factors to ((x - y)(x + y) = 300). The factors of 300 can be paired to find suitable values for (x) and (y). One solution is (x = 19) and (y = 11), as (19^2 - 11^2 = 361 - 121 = 240). Another solution is (x = 20) and (y = 10), since (20^2 - 10^2 = 400 - 100 = 300).
You prepare a solution by dissolving a known mass of solute into a specific amount of solvent. In solutions, M is the molarity, or moles of solute per liter of solution. For 300 ml of a 0.1 M Na CL solution from a solid Na CL solution and water you need water and sodium chloride.
300 = 100*3 So sqrt(300) = 10*sqrt(3)
To calculate the moles of potassium hydroxide needed, use the formula: moles = molarity * volume (in liters). First, convert 300 mL to liters (0.3 L). Then, moles = 0.250 mol/L * 0.3 L = 0.075 moles of potassium hydroxide needed to prepare the solution.
10 sqrt(3)
To find the moles of NaOH needed, use the formula: moles = concentration (molarity) x volume (liters). First, convert 300 mL to liters (0.3 L). Then, calculate: moles = 0.2 mol/L x 0.3 L = 0.06 moles. Therefore, 0.06 moles of NaOH are needed to prepare 300 mL of a 0.2 M solution.
I think you want: √300 = √(100 x 3) = √100 x √3 = 10√3
Let Q be the quantity of 80% solution required then (300 - Q) is the quantity of 30% solution as together the two solutions must equal 300. Then, [80 x Q] + [30 x (300 - Q)] = [40 x 300] 80Q + 9000 - 30Q = 12000 50Q = 3000 Q = 60...........which means (300 - Q) = 240 60ml of 80% acid solution + 240ml of 30% solution produces 300ml of 40% solution.
SC-300 Practice Test is the best way to prepare and pass the SC-300 exam
To prepare the 1.2 M NaOH solution, you need to dilute the 5.5 M NaOH solution. By using the formula C1V1 = C2V2 (where C1 is initial concentration, V1 is initial volume, C2 is final concentration, and V2 is final volume), you can calculate the volume of the 5.5 M NaOH solution needed to make 300 ml of 1.2 M NaOH solution. In this case, V1 would be the volume of the 5.5 M NaOH solution you need to calculate.
To prepare 1000 ml of 70% alcohol solution, you would need to mix 700 ml of 95% alcohol with 300 ml of water. Starting with a base of 95% alcohol ensures that the final solution will be at least 70% alcohol.
300 Length of Noah's Ark in Cubits
30 degrees explanation 2Cosx-radical 3=0 Then 2cosx=radical 3 and cos x=(radical 3)/2 Now remember that cos 300 is (radical 3)/2 from the 30/60/90 triangle. So the answer is 30 degrees.