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I think you want: √300 = √(100 x 3) = √100 x √3 = 10√3
Let Q be the quantity of 80% solution required then (300 - Q) is the quantity of 30% solution as together the two solutions must equal 300. Then, [80 x Q] + [30 x (300 - Q)] = [40 x 300] 80Q + 9000 - 30Q = 12000 50Q = 3000 Q = 60...........which means (300 - Q) = 240 60ml of 80% acid solution + 240ml of 30% solution produces 300ml of 40% solution.
No, 18.75 is the solution.
The statement "300 is between 100 and 400" is equivalent to: 100 < 300 < 400 Or the equivalent: 300 > 100 AND 300 < 400. If you check these statements and see that they are true, then 300 is between the two numbers.
The pair of square numbers that has a difference of 300 can be found by solving the equation (x^2 - y^2 = 300), which factors to ((x - y)(x + y) = 300). The factors of 300 can be paired to find suitable values for (x) and (y). One solution is (x = 19) and (y = 11), as (19^2 - 11^2 = 361 - 121 = 240). Another solution is (x = 20) and (y = 10), since (20^2 - 10^2 = 400 - 100 = 300).
You prepare a solution by dissolving a known mass of solute into a specific amount of solvent. In solutions, M is the molarity, or moles of solute per liter of solution. For 300 ml of a 0.1 M Na CL solution from a solid Na CL solution and water you need water and sodium chloride.
300 = 100*3 So sqrt(300) = 10*sqrt(3)
To calculate the moles of potassium hydroxide needed, use the formula: moles = molarity * volume (in liters). First, convert 300 mL to liters (0.3 L). Then, moles = 0.250 mol/L * 0.3 L = 0.075 moles of potassium hydroxide needed to prepare the solution.
10 sqrt(3)
To find the moles of NaOH needed, use the formula: moles = concentration (molarity) x volume (liters). First, convert 300 mL to liters (0.3 L). Then, calculate: moles = 0.2 mol/L x 0.3 L = 0.06 moles. Therefore, 0.06 moles of NaOH are needed to prepare 300 mL of a 0.2 M solution.
I think you want: √300 = √(100 x 3) = √100 x √3 = 10√3
Let Q be the quantity of 80% solution required then (300 - Q) is the quantity of 30% solution as together the two solutions must equal 300. Then, [80 x Q] + [30 x (300 - Q)] = [40 x 300] 80Q + 9000 - 30Q = 12000 50Q = 3000 Q = 60...........which means (300 - Q) = 240 60ml of 80% acid solution + 240ml of 30% solution produces 300ml of 40% solution.
SC-300 Practice Test is the best way to prepare and pass the SC-300 exam
Use M1V1=M2V2 Where M is the concentration (5.5 m for M1 and 1.2 m for M2) and V is volume V1 is 300 ml and V2 is your unknown. Using this calculation for other questions be sure that units are all the same. So all molarities and all mL in this example.
To prepare 1000 ml of 70% alcohol solution, you would need to mix 700 ml of 95% alcohol with 300 ml of water. Starting with a base of 95% alcohol ensures that the final solution will be at least 70% alcohol.
300 Length of Noah's Ark in Cubits
30 degrees explanation 2Cosx-radical 3=0 Then 2cosx=radical 3 and cos x=(radical 3)/2 Now remember that cos 300 is (radical 3)/2 from the 30/60/90 triangle. So the answer is 30 degrees.